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Maksim231197 [3]

3 years ago

10

What is the precent of 2 is 8?

1 answer:

Vlad [161]3 years ago

3 0

2 * x/100 = 8

x/100 = 4

x = 400

400%

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Two machines are used for filling glass bottles with a soft-drink beverage. The filling process have known standard deviations s

stellarik [79]

Answer:

a. We reject the null hypothesis at the significance level of 0.05

b. The p-value is zero for practical applications

c. (-0.0225, -0.0375)

Step-by-step explanation:

Let the bottles from machine 1 be the first population and the bottles from machine 2 be the second population.

Then we have $n_{1} = 25$ , $\bar{x}_{1} = 2.04$ , $\sigma_{1} = 0.010$ and $n_{2} = 20$ , $\bar{x}_{2} = 2.07$ , $\sigma_{2} = 0.015$ . The pooled estimate is given by

$\sigma_{p}^{2} = \frac{(n_{1}-1)\sigma_{1}^{2}+(n_{2}-1)\sigma_{2}^{2}}{n_{1}+n_{2}-2} = \frac{(25-1)(0.010)^{2}+(20-1)(0.015)^{2}}{25+20-2} = 0.0001552$

a. We want to test $H_{0}: \mu_{1}-\mu_{2} = 0$ vs $H_{1}: \mu_{1}-\mu_{2} \neq 0$ (two-tailed alternative).

The test statistic is $T = \frac{\bar{x}_{1} - \bar{x}_{2}-0}{S_{p}\sqrt{1/n_{1}+1/n_{2}}}$ and the observed value is $t_{0} = \frac{2.04 - 2.07}{(0.01246)(0.3)} = -8.0257$ . T has a Student's t distribution with 20 + 25 - 2 = 43 df.

The rejection region is given by RR = {t | t < -2.0167 or t > 2.0167} where -2.0167 and 2.0167 are the 2.5th and 97.5th quantiles of the Student's t distribution with 43 df respectively. Because the observed value $t_{0}$ falls inside RR, we reject the null hypothesis at the significance level of 0.05

b. The p-value for this test is given by $2P(T$ 0 (4.359564e-10) because we have a two-tailed alternative. Here T has a t distribution with 43 df.

c. The 95% confidence interval for the true mean difference is given by (if the samples are independent)

$(\bar{x}_{1}-\bar{x}_{2})\pm t_{0.05/2}s_{p}\sqrt{\frac{1}{25}+\frac{1}{20}}$ , i.e.,

$-0.03\pm t_{0.025}0.012459\sqrt{\frac{1}{25}+\frac{1}{20}}$

where $t_{0.025}$ is the 2.5th quantile of the t distribution with (25+20-2) = 43 degrees of freedom. So

$-0.03\pm(2.0167)(0.012459)(0.3)$ , i.e.,

(-0.0225, -0.0375)

8 0

3 years ago

Graph the line with slope −2 passing through the point , 5−1.

Allisa [31]

<u>Answer:</u>

<u>y+1=-2(x-5)</u> - Point Slope Form

<u>y=-2x+9</u> - Slope Intercept Form

<u></u>

Step-by-step explanation:

We will be using point-slope formula, as attached in a picture below.

1) Plug in the slope -2 as "m" in point slope form, along with the two points, (5, -1)

<u>y+1=-2(x-5)</u>

2) Next, if you want to put the line into slope-intercept form, you will need to distribute -2 to x and -5:

y+1=-2x+10

3) Now, subtract 1 from both sides:

<u>y=-2x+9</u>

6 0

3 years ago

Shiloh is splitting a quart of mac n cheese with seven friends If all 8 of them share the quart equally, how many cups will each

NNADVOKAT [17]

Answer:

half a cup

Step-by-step explanation:

there are 4 cups in a quart they will each get half a cup

3 0

2 years ago

Trevor paints 1/6 of the fence. how many days will it take for him to paint 3/4 of it

Levart [38]

4 and a half days

3/4 ÷ 1/6 =
3/4 × 6/1=
18/4=
4.5 days

hope this helps :)

4 0

3 years ago

Write a linear function f with f(−9)=10 and f(−1)=−2

pashok25 [27]

First we need to find the slope of the function

The slope of a function is equal to

$\frac{f(x_2)-f(x_1)}{x_2-x_1}$

So now we plug this into the equation and find the slope (M will represent the slope)

$m=\frac{10--2}{-9--1}\\m=\frac{12}{-8}\\m=-\frac{3}{2}$

So the slope is -3/2

Now we can use point-slope form.

Point slope form is represented by

$Y-Y_1=m(X-X_1)$

So when we plug in our values we get

$Y--2=-3/2(X--1)\\Y+2 = -3/2(X+1)\\Y+2 = -3/2X-3/2\\Y=-3/2X-7/2$

So the equation is

Y = -3/2X-7/2

6 0

3 years ago