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sesenic [268]
3 years ago
10

Which event is LEAST LIKELY to occur?

Mathematics
1 answer:
lisabon 2012 [21]3 years ago
5 0
A because it’s the closet to 0!
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The sum of three consecutive even numbers is 78. What is the first number
Rus_ich [418]
Even consecutive numbers are 2 apart
(2,4,6, example)
so they are
n,n+2,n+4
their sum is 78
n+n+2+n+4=78
3n+6=78
minus 6
3n=72
divide 3
n=24
smallest is 24
3 0
3 years ago
Read 2 more answers
Ishi bought a canvas and 8 tubes of paint for $24.95. If the canvas costs $6.95, how much did each tube of paint cost?
pashok25 [27]
2.25 dollars for each tube of paint. you just have to divide 18 and 8
7 0
3 years ago
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find an equation of the line that bisects the acute angle formed by the graphs of 3x+5y+2=0 and 5x+3y-2=0
Aleks [24]

Answer:

x+ y = 0  

and

-2x + 5y + 2 = 0

Step-by-step explanation:

given line

3x+5y+2=0

5x+3y-2=0

solution

when two line bisect each other then line equation of bisector is express as

\frac{|A1x+B1y+C1|}{\sqrt{A1^2+B1^2+C1^2}} = \frac{|A2x+B2y+C2|}{\sqrt{A2^2+B2^2+C2^2}}      .........................1

and here

A1 = 3

B1  = 5

C1 = 2

and

A2 = 5

B2  = 3

C2 = -2

so now put value in equation 1 we get

\frac{|3x+5y+2|}{\sqrt{3^2+5^2+2^2}} = \frac{|5x+3y-2|}{\sqrt{3^2+5^2+(-2)^2}}    

solve it we get

-2x + 5y + 2 = 0    ..........1

and

3x+5y+2 = - ( 5x+3y-2 )

solve it we get

8x + 8y = 0

x + y = 0     ................2

4 0
3 years ago
four 3 megawatt wind turbines can supply enough electricity to power 3000 homes. How many turbines would be required to power 55
fiasKO [112]

Answer:

The number of turbines is 74

Step-by-step explanation:

* Lets explain how to solve the problem

- Four 3 megawatt wind turbines can supply enough electricity

 to power 3000 homes

∴ The number of turbines is 4

∵ Each turbine give 3 megawatt

∴ The four turbines give ⇒ 4 × 3 = 12 megawatt

- This quantity give enough electricity to power 3000 homes

∴ The number of homes for the 12 megawatt is 3000

- We need to find how many turbines can cover enough electricity

  to power 55,000 homes, so we must to know the quantity of

  electricity that be enough to power 55,000 homes

* <em>Lets use the cross multiplication to solve the problem</em>

∵         megawatt    :     number of homes

                  12          :              3,000

                  ?            :            55,000

- <em>By using cross multiplication</em>

∴ ?=\frac{(55,000)(12)}{3,000}=\frac{660,000}{3000}=220

∴ The enough electricity to power 3000 homes = 220 megawatt

∵ Each turbine gives 3 megawatt

- Find the number of turbines divides the total megawatt by the the

  megawatt of one turbine

∴ The number of turbines = 220 ÷ 3 = 73.3

- If we take 73 only the electricity will not be enough to cover all

 homes, so we must to take 74 turbines

∴ The number of turbines is 74

5 0
4 years ago
Classifying triangles <br>​
Ksenya-84 [330]

Answer:

B. Right

E. Scalene

7 0
3 years ago
Read 2 more answers
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