Answer:
Step-by-step explanation:
Given problems are absolute value problems, So we need to plug the values of given parameters and get the final result.
We have given here,
a =-2 , b = 3 , c = -4 and d = -6
Now we know that An absolute function always gives a positive value.
Let's apply this strategy in the given problems.
1. ║a+b║
Plug a= -2 and b = 3
We get, ║-2+3║=║1║= 1
2. 5║c+b║
Plug c= -4 and b=3
i.e. 5║-4 + 3║= 5║-1║=5×1 = 5
3. a+b║c║
Plug values a= -2 , b=3 and c=-4
i.e -2 +3║-4║ = -2 + 3×4 = -2 + 12 = 10
4. ║a+c║÷(-d)
i.e ║-2 + (-4)║÷(-6) = ║-6║÷(-6) = 6÷(-6) = -1
5. 3║a+d║+b
i.e 3║-2+(-6)║+3 = 3║-8║+3 = 3×8 +3 = 27
Answer:
c.-10
Step-by-step explanation:
4x+2=11
x=9/4...(1)
now,
-4x-1=-4x(9/4)-1=-10
If u raise a power to another power, then u multiply the powers. In this case, u can simplify to 6^2p =6^10
Now you have like bases, so you can set the powers equal to each other. So now, 2p=10. Now p=5
