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stellarik [79]
2 years ago
15

Find the factors of x3−7x−6

Mathematics
2 answers:
Misha Larkins [42]2 years ago
5 0

Step-by-step explanation:

Factor {x}^{3}-7x-6x3−7x−6 using Polynomial Division.

({x}^{2}-x-6)(x+1)(x2−x−6)(x+1)

2

 



Factor {x}^{2}-x-6x2−x−6.

(x-3)(x+2)(x+1)(x−3)(x+2)(x+1)

Lyrx [107]2 years ago
4 0

Answer:

  • B. (x−3)(x+2)(x+1)

Step-by-step explanation:

Possible options are 1 or 2 as each has odd number of negative coefficients.

<u>Open parenthesis and verify:</u>

  • (x+3)(x+2)(x−1) = ³ + 4x² + x - 6, false
  • (x−3)(x+2)(x+1) = x³ - 7x - 6, true

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LUCKY_DIMON [66]

Answer:

1.) $1.07

2.) $2.25

3.) $14.20

Step-by-step explanation:

1.) Toonie = 2 CAD

CAD = USD $1.57

$1.57 - $0.50 = $1.07 (USD)

2.) $2.75 - $5 = $2.25 (USD)

3.) $20 x 4 = 80

$80 - $65.80 = $14.20 (USD)

Hope this helped!

8 0
2 years ago
A ticket to a movie theatre for a student is $7. The cost for an adult is $2 more than for a student. How much would it cost 13
MakcuM [25]

Answer: it would cost a total of $194

Step-by-step explanation:

A ticket to a movie theatre for a student is $7. The cost for an adult is $2 more than for a student.

If student ticket costs $x, adult ticket would cost x + 2

This means that the cost for an adult is

7 + 2 = $9

The cost of 13 adult tickets to the movie theatre would be

13 × 9 = $117.

The cost of 11 student tickets to the movie theatre would be

11 × 7 = $77

Total cost of 13 adult tickets and 11 student tickets would be

117 + 77 = $194

3 0
2 years ago
What is the answer to this inequality?<br> (x+7)&gt;80
Crank

Answer:

x > 73

Step-by-step explanation:

x+7 > 80

subtract 7 from both sides

x + 7 - 7 > 80 - 7

x > 73

-Chetan K

5 0
2 years ago
How to divide this? WITH SOLUTION​ i need the answer pls​s​
Olin [163]

Answer:

Step-by-step explanation:Please mark me as the brainlyest

4 0
3 years ago
Suppose that a box contains 6 cameras and that 3 of them are defective. A sample of 2 cameras is selected at random. Define the
mezya [45]

Answer: 1/5, 1/2, 0.

Step-by-step explanation:

given data:

no of cameras = 6

no of cameras defective = 3

no of cameras selected = 2

Let p(t):=P(X=t)

p(2)=m/n,

m=binomial(3,2)=3!/2!= 3

n=binomial(6,2)=6!/2!/4! = 15

p(3)= 3/15

= 1/5.

p(1)=m/n,

m=binomial(6,1)*binomial(2,2)=6!/1!/4!*2!/2!/0!= 7.5

n=binomial(6,2)= 15

p(2)= 7.5/15

= 1/2

p(0)=m/n,

m=0

p(0)=0

7 0
3 years ago
Read 2 more answers
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