2. Find the compound interest on Rs.25, 000 after 2 years compounded

sveticcg [70]

2/3
divide by 17

34/17 is 2
51/17 is 3

5 0

3 years ago

when 1 is added to a number and the answer is trebled , it gives the same result as doubling the number and then adding 4, find

Phoenix [80]

X - the number
3(x+1)=2x+4
3x+3=2x+4
3x-2x=4-3
x=1

7 0

3 years ago

Consider the polynomial f(x)=2x^5-3x^4+x-6 (x )equals 2 x Superscript 5 Baseline minus 3 x Superscript 4 Baseline plus x minus 6

melamori03 [73]

Answer:

degree of polynomial = 5

leading term = $2x^{5}$

leading coefficient = 2

constant term = -6

Step-by-step explanation:

$f(x) = 2x^{5}-3x^{4}+x-6$

(i) The degree of the polynomial = 5. That is, the highest power of x

(ii) Leading term = $2x^{5}$ . This is the term with the highest power of x.

(iii) Leading Coefficient = 2. That is, the coefficient of the leading term ( $2x^{5}$ )

(iv) Constant term = -6. This is the term that is independent of x or the term in which x doesn't appear.

3 0

3 years ago

Test the hypothesis using the P value approach. Be sure the verify the requirements of the test.

Andreas93 [3]

Answer:

$p_v =2*P(z$

If we compare the p value and using the significance level given $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion is not significantly different from 0.77.

Step-by-step explanation:

1) Data given and notation

n=500 represent the random sample taken

X=380 represent the number of people with some characteristic

$\hat p=\frac{380}{500}=0.76$ estimated proportion of adults that said that it is morally wrong to not report all income on tax returns

$p_o=0.76$ is the value that we want to test

$\alpha=0.05$ represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

2) Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the true proportion is 0.7 .:

Null hypothesis: $p=0.77$

Alternative hypothesis: $p \neq 0.77$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

<em>Check for the assumptions that he sample must satisfy in order to apply the test </em>

a)The random sample needs to be representative: On this case the problem no mention about it but we can assume it.

b) The sample needs to be large enough

$np_o =500*0.77=385>10$

$n(1-p_o)=384*(1-0.77)=115>10$

3) Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.76-0.77}{\sqrt{\frac{0.77(1-0.77)}{500}}}=-0.531$

4) Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.05$ . The next step would be calculate the p value for this test.

Since is a bilateral test the p value would be:

$p_v =2*P(z$

If we compare the p value and using the significance level given $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion is not significantly different from 0.77.

6 0

4 years ago

Which number line represents the solution set for the end equality 3x < -9

shepuryov [24]

divide both sides by 3

so, you'll get x<-3

that's your solution

4 0

3 years ago