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Gemiola [76]
3 years ago
6

2. Find the compound interest on Rs.25, 000 after 2 years compounded

Mathematics
1 answer:
Allushta [10]3 years ago
6 0

Answer:25,000 in 2 years at annual compound interest, if the rates for the successive years be 4% and 5% per annum respectively is: (1) Rs. 30,000 (2) Rs. 26,800 fa) Rs.

A=P[1+  

100

r

​  

]  

n

 

⇒  A=Rs.25,000×(  

100

106

​  

)  

3

 

⇒  25,000×  

50

53

​  

×  

50

53

​  

×  

50

53

​  

 

⇒  A=Rs.29,775.40

⇒  CI=A−P

⇒  Rs.29,775.40−Rs.25,000

∴   CompoundInterest=Rs.4775.40.

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Arisa [49]
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</span><span>
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</span><span>
2 B C D x </span><span>4 = </span><span>D C B 2</span>
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2 B C 8 x <span>4 = </span><span>8 C B 2</span>
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We try B=1

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3 years ago
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storchak [24]
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If h(x) = 4x – 3 and p(x) = x2 – 3x, find p(-3)<br><br> 18<br> 0<br> -3
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Step-by-step explanation:

To find p(-3), you plug -3 into p(x) and solve.

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7 0
3 years ago
ALOT OF POINTS IF YOU HELP ME PLEASE EXPLAIN ​
Svetllana [295]

Answer:

Helena gave the answer as (7y²z + 6yz²- 5 - 3yz² + 2) which is equivalent to (7y²z + 3yz² - 3).

Step-by-step explanation:

Misha's group was asked to write an expression equivalent to  

7y²z + 3yz² - 3

When Mr. Chen checked their answers, he found only one to be correct.

And she was Helena.

Helena gave the answer as (7y²z + 6yz²- 5 - 3yz² + 2) which is equivalent to (7y²z + 3yz² - 3).  

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