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lara [203]
3 years ago
10

Name the shape of the hanging wire

Mathematics
2 answers:
GREYUIT [131]3 years ago
8 0

Answer:

sorry Don didn't know ksjshsndjd

lbvjy [14]3 years ago
8 0
Where? you didn’t attach it
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Anyone know wether gcse are techer assessed or wht in england this year
miskamm [114]

Answer:

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6 0
3 years ago
What is the degree of the equation?
wolverine [178]

Answer:

1 (give brainliest plss)

Step-by-step explanation:

Step-1 : Multiply the coefficient of the first term by the constant 5 • -8 = -40

Step-2 : Find two factors of -40 whose sum equals the coefficient of the middle term, which is -3 .

-40 + 1 = -39

-20 + 2 = -18

-10 + 4 = -6

-8 + 5 = -3 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -8 and 5

5x2 - 8x + 5x - 8

Step-4 : Add up the first 2 terms, pulling out like factors :

x • (5x-8)

Add up the last 2 terms, pulling out common factors :

1 • (5x-8)

Step-5 : Add up the four terms of step 4 :

(x+1) • (5x-8)

Which is the desired factorization

4 0
3 years ago
Read 2 more answers
This is the last question PLSSSSS HELP
DanielleElmas [232]

Answer:

D

Step-by-step explanation:

The volume of a cylinder is pi * r^2 * h

A) V = 3.14 * (0.7/2)^2 * 6.2 = 2.4 m^2

B) V = 3.14 * (0.9/2)^2 * 3.4 = 2.2 m^2

C) V = 3.14 * (1.2/2)^2 * 6.8 = 7.7 m^2

D) V = 3.14 * (1.4/2)^2 * 6.2 = 9.5 m^2

6 0
2 years ago
Read 2 more answers
6. Find the values for each of the following: a. 3 times 5 in Z1o b. 3 times 5 in Zs c. 3 times 5 in Z3 e. 5 3 in Z1o
Anettt [7]

Answer:  The calculations are done below.

Step-by-step explanation:  We are given to find the values for each of the following :

(A) 3 times 5 in \mathbb{Z}_{10}.

We know that

\mathbb{Z}_{10}=\{0,1,2,3,4,5,6,7,8,9\}(\textup{mod}10).

Therefore, we get

3\times5=15(\textup{mod}10)=5.

(B) 3 times 5 in \mathbb{Z}_{5}.

We know that

\mathbb{Z}_{5}=\{0,1,2,3,4\}(\textup{mod}5).

Therefore, we get

3\times5=15(\textup{mod}5)=0.

(C) 3 times 5 in \mathbb{Z}_{3}.

We know that

\mathbb{Z}_{3}=\{0,1,2\}(\textup{mod}3).

Therefore, we get

3\times5=15(\textup{mod}3)=0.

(D) 5 times 3 in \mathbb{Z}_{10}.

We know that

\mathbb{Z}_{10}=\{0,1,2,3,4,5,6,7,8,9\}(\textup{mod}10).

Therefore, we get

5\times3=15(\textup{mod}10)=5.

Thus, the required values are evaluated.

8 0
3 years ago
If t and m are positive, t^2 + m^2 = 64 and (t+m)^2 = 98, what is tm?
madam [21]

Answer:

17

Step-by-step explanation:

t^2 + m^2 = 64

(t+m)^2 = 98

(t+m)^2 = t^2 +2tm+ m^2

==>

t^2 +2tm+ m^2 = 98

t^2+m^2+2tm=98

64+ 2tm=98

2tm = 98 -64

2tm=34

tm= 34/2

tm = 17

8 0
2 years ago
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