Step 1
Save your work and close all programs. You will be restarting your computer during the process.
Step 2
Click “Start” from the task bar and then choose “All Programs.”
Step 3
Click “Accessories” from the program menu. Choose “System Tools” from the side pop-out menu and then select “System Restore.”
Step 4
Click “Restore my computer to an earlier time” from the Welcome screen. Click “Next” at the bottom.
Step 5
Choose a date in bold from the calendar shown on the Restore Point page. The date that you choose should be an earlier one, like a day or two before the deletion occurred. Click “Next” at the bottom of the window.
Step 6
Click “Next” on the next page. The restoration begins, and your computer will restart.
Step 7
Click “OK” from the completion window that appears when your computer loads again.
I’m pretty sure it’s miner
“I’ll give you head I mean brainiest”
Answer:
Yes, overloading is one of the methods which are popular in programming language. Overloading basically refers to the same function but different signature called function overloading or method overloading. It is the ability to define the multiples method by using the single identifier.
The overloading is important because it has the ability to design the multiple method by using similar name. It also provide the high flexibility to the programmers to call the same method in the data. overloading basically provide the high clarity in the code.
Overloading is used to achieved the compile time polymorphism.
Following are program of function overloading in c++ are:
Class abc // creating class
{
public:
int p;
void fun() // function fun with no parameter/
{
cout<<” hello “;
}
void fun(int a) // function fun with parameter
{
p=a;
cout<<p;
}
};
int main() // main function
{
abc ob; // creating object
ob.fun();// print hello;
ob.fun(6);// print 6
return 0;
}
Explanation:
In this program the function fun() have same name but different signature in the main method we create the object of class abc i.e ob. ob.fun() this statement called the function with no parameter and ob.fun(6) this statement will called the function with integer parameter.
Answer:
see explaination for program code
Explanation:
scalar_product = 0
li=[]
li2=[]
#reading numbers1.txt and numbers2.txt intoli and li2 respectively
with open('numbers1.txt') as n1, open('numbers2.txt') as n2:
for line1 in n1:
li.append(int(line1))
for line2 in n2:
li2.append(int(line2))
#storing min list size into variable l
a=len(li)
b=len(li2)
if a<b:
l=a
else:
l=b
#calculating scalar product
for i in range(l):
scalar_product=scalar_product+li[i]*li2[i]
print("scalar product is",scalar_product)
Magnetically
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