Hi! I don’t know what any of this means but I just wanted to tell you that I hope you have an amazing day and god/allah/etc bless you :)
Answer:
12
Step-by-step explanation:
The ratio of cars to trucks to motorcycles is $4:3:2.
If there are $42$ cars and trucks total,
To get how many motorcycles are there
Sum up the ratio of cars and trucks 4:3= 4+3 = 7
Sum up the ratio of cars and trucks and motorcycles
4+3+2 =9
Let the total number of cars and trucks and motorcycles be represented as A
The total number of cars and trucks in the question is 42
(7/9) x A = 42
7A/9 = 42
cross multiply
7A = 42×9 = 378
A= 378/7 = 54
The total number of cars and trucks and motorcycles is 54
To get the number of motorcycles can be calculated through
a. The total number of cars and trucks and motorcycles subtracted by the number of cars and trucks = 54-42=12 or use the ratio which is
2/9 × 54 = 2×6=12
9514 1404 393
Answer:
f^-1(x) = 4+∛((x-6)/5)
Step-by-step explanation:
To find the inverse function, solve ...
x = f(y)
then write the answer in functional form.
![\displaystyle x=f(y)\\\\x=5(y-4)^3+6\\\\x-6=5(y-4)^3\\\\\frac{x-6}{5}=(y-4)^3\\\\\sqrt[3]{\frac{x-6}{5}}=y-4\\\\y=4+\sqrt[3]{\frac{x-6}{5}}\\\\\boxed{f^{-1}(x)=4+\sqrt[3]{\frac{x-6}{5}}}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20x%3Df%28y%29%5C%5C%5C%5Cx%3D5%28y-4%29%5E3%2B6%5C%5C%5C%5Cx-6%3D5%28y-4%29%5E3%5C%5C%5C%5C%5Cfrac%7Bx-6%7D%7B5%7D%3D%28y-4%29%5E3%5C%5C%5C%5C%5Csqrt%5B3%5D%7B%5Cfrac%7Bx-6%7D%7B5%7D%7D%3Dy-4%5C%5C%5C%5Cy%3D4%2B%5Csqrt%5B3%5D%7B%5Cfrac%7Bx-6%7D%7B5%7D%7D%5C%5C%5C%5C%5Cboxed%7Bf%5E%7B-1%7D%28x%29%3D4%2B%5Csqrt%5B3%5D%7B%5Cfrac%7Bx-6%7D%7B5%7D%7D%7D)
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The graph shows the function and its inverse to be reflections of each other in the line y=x, as they should be.
Answer:
x=12
Step-by-step explanation:
3x/6 + 2 = 8
Subtract 2 from each side
3x/6 + 2-2 = 8-2
3x/6 =6
Multiply each side by 6/3
6/3 * 3/6 x = 6 *6/3
x = 36/3
x = 12
The asymptote is the line the graph comes close to but never touches, so if you graph it out you should be able to see it! Sorry I couldn't help any more but good luck
