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2 years ago

DUE IN 5 MINUTES!!!1!!11!1!!1 123 + 392 - 234 x 2 ÷ 3 + 223 x 14 =

Mathematics

1 answer:

Eva8 [605]2 years ago

3 0

Answer: 3481

Step-by-step explanation:

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A board is 7 feet 9 inches long. How long is it in inches?

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93 inches - 7 times 12 (inches in a foot)is 84 plus 9 is 93 inches.

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3 years ago

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(27 thousands 3 hundreds 5 ones) x 10

anyanavicka [17]

Answer:

Two hundred seventy three thousand and fifty .

Step-by-step explanation:

Given : (27 thousands 3 hundreds 5 ones) x 10

Solution:

27 thousands 3 hundreds 5 ones = 27,305

So, $27,305 \times 10$

$273,050$

Periods are counted from last .

The 1st period consists of ones, tens and hundred.

The 2nd period consists of thousand, 10 thousand and 100 thousands.

The 3rd period consists of million, 10 million and 100 million.

So, 273,050 is Two hundred seventy three thousand and fifty

Hence (27 thousands 3 hundreds 5 ones) x 10 is Two hundred seventy three thousand and fifty .

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Solve the literal equation for y. 2x-4y=20

Phoenix [80]

2x -4y=20
-4y=-2x+20
Y= 1/2x - 5 that’s the answer

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3 years ago

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Anyone know how to do this? will give brainlest! if you cant help, have a great day!!!

Aleks04 [339]

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write the logarithm as a sum or difference of logarithms. simplify each term as much as possible. log4(6ab)

Dominik [7]

The logarithm written as a sum of logarithm and simplified as much as possible is $\frac{1}{2} +log_{4 }3 + log_{4 }a + log_{4 }b$

<h3>Simplifying Logarithms</h3>

From the question, we are to write the given logarithm expression as a sum or difference of logarithms

The given logarithm is

$log_{4 }6ab$

This can be written as

$log_{4 }6 \times a \times b$

From one of the rules of logarithm, we have that

$log_{x }yz= log_{x }y + log_{x }z$

Thus,

$log_{4 }6 \times a \times b$ becomes

$log_{4 }6 + log_{4 }a + log_{4 }b$

This can be further simplified into

$log_{4 }3 \times 2 + log_{4 }a + log_{4 }b$

$log_{4 }3 + log_{4 }2 + log_{4 }a + log_{4 }b$

If desired, this can be further simplified into

$log_{4 }3 + log_{2^{2} }2 + log_{4 }a + log_{4 }b$

$log_{4 }3 + \frac{1}{2} log_{2}2 + log_{4 }a + log_{4 }b$

$log_{4 }3 + \frac{1}{2} (1)+ log_{4 }a + log_{4 }b$

$\frac{1}{2} +log_{4 }3 + log_{4 }a + log_{4 }b$

Hence, the logarithm written as a sum of logarithm and simplified as much as possible is $\frac{1}{2} +log_{4 }3 + log_{4 }a + log_{4 }b$

Learn more on Simplifying logarithms here: brainly.com/question/17851187

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8 0

1 year ago