Ask question

Ask question

All categories

3 years ago

9

A spinner has 6 sectors, half of which are red and half of which are black. If the radius of the spinner is 3 inches, what is th

e area of the red sectors?

2 answers:

vesna_86 [32]3 years ago

6 0

Answer is Thirty Six

scZoUnD [109]3 years ago

5 0

Answer:

Make me Brilliant

Step-by-step explanation:

Make me Brilliant then you are legend

You might be interested in

Cost to store 155 mark up 30

pickupchik [31]

Answer:

201.50

Step-by-step explanation:

SP = CP + markup

155 + 30% =
155*1.3 =
201.50

5 0

2 years ago

Write and simplify the integral that gives the arc length of the following curve on the given interval b. If necessary, use tech

LiRa [457]

Answer:

L = 4.103

Step-by-step explanation:

we have length of curve

$L = \int\limits^b_a {\sqrt{(f'(x))²+1} } \, dx$

where $f(x) = d/dx(3*in(x)) = 3/x$

substituting for f(x), we have $L = \int\limits^5_2 {\sqrt{(3/x)²+1} } \, dx$

(since the limit is 2≤ x ≤5)

solving, $L = \int\limits^5_2 {\sqrt{9/x²+1} } \, dx$

Simplifying this integral, we have

L = 4.10321

8 0

3 years ago

What is the best estimate for 591.3 divided by 29

Katena32 [7]

Answer:

about 20

Step-by-step explanation:

The numbers round to 600/30 = 20, which is a reasonable estimate.

You can refine this by doing the next step of long division:

29×20 = 580

Subtracting this from 591.3 give 11.3, so the fraction is ...

11.3/29 ≈ 10/30 = 1/3

A better estimate is 20 1/3.

_____

A calculator tells you the quotient is about 20.3897.

4 0

2 years ago

Which statement is true?

love history [14]

<h2>Hello!</h2>

The answer is:

The second option,

$(\sqrt[m]{x^{a} } )^{b}=\sqrt[m]{x^{ab} }$

<h2>Why?</h2>

Discarding each given option in order to find the correct one, we have:

<h2>First option,</h2>

$\sqrt[m]{x}\sqrt[m]{y}=\sqrt[2m]{xy}$

The statement is false, the correct form of the statement (according to the property of roots) is:

$\sqrt[m]{x}\sqrt[m]{y}=\sqrt[m]{xy}$

<h2>Second option,</h2>

$(\sqrt[m]{x^{a} } )^{b}=\sqrt[m]{x^{ab} }$

The statement is true, we can prove it by using the following properties of exponents:

$(a^{b})^{c}=a^{bc}$

$\sqrt[n]{x^{m} }=x^{\frac{m}{n} }$

We are given the expression:

$(\sqrt[m]{x^{a} } )^{b}$

So, applying the properties, we have:

$(\sqrt[m]{x^{a} } )^{b}=(x^{\frac{a}{m}})^{b}=x^{\frac{ab}{m}}\\\\x^{\frac{ab}{m}}=\sqrt[m]{x^{ab} }$

Hence,

$(\sqrt[m]{x^{a} } )^{b}=\sqrt[m]{x^{ab} }$

<h2>Third option,</h2>

$a\sqrt[n]{x}+b\sqrt[n]{x}=ab\sqrt[n]{x}$

The statement is false, the correct form of the statement (according to the property of roots) is:

$a\sqrt[n]{x}+b\sqrt[n]{x}=(a+b)\sqrt[n]{x}$

<h2>Fourth option,</h2>

$\frac{\sqrt[m]{x} }{\sqrt[m]{y}}=m\sqrt{xy}$

The statement is false, the correct form of the statement (according to the property of roots) is:

$\frac{\sqrt[m]{x} }{\sqrt[m]{y}}=\sqrt[m]{\frac{x}{y} }$

Hence, the answer is, the statement that is true is the second statement:

$(\sqrt[m]{x^{a} } )^{b}=\sqrt[m]{x^{ab} }$

Have a nice day!

6 0

2 years ago

Consider the following hypothesis test: H0: μ1 - μ2 = 0 Ha: μ1 - μ2 ≠ 0 There are two independent samples taken from the two pop

nlexa [21]

Answer:

The value of the test statistic is $z = 1.78$

Step-by-step explanation:

Before finding the test statistic, we need to understand the central limit theorem and subtraction of normal variables.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Subtraction between normal variables:

When two normal variables are subtracted, the mean is the difference of the means, while the standard deviation is the square root of the sum of the variances.

Sample 1:

$\mu_1 = 110, s_1 = \frac{7.2}{\sqrt{81}} = 0.8$

Sample 2:

$\mu_2 = 108, s_2 = \frac{6.3}{\sqrt{64}} = 0.7875$

The test statistic is:

$z = \frac{X - \mu}{s}$

In which X is the sample mean, $\mu$ is the value tested at the null hypothesis, and s is the standard error.

0 is tested at the null hypothesis:

This means that $\mu = 0$

Distribution of the difference:

$X = \mu_1 - \mu_2 = 110 - 108 = 2$

$s = \sqrt{s_1^2+s_2^2} = \sqrt{0.8^2+0.7875^2} = 1.1226$

What is the value of the test statistic?

$z = \frac{X - \mu}{s}$

$z = \frac{2 - 0}{1.1226}$

$z = 1.78$

The value of the test statistic is $z = 1.78$

5 0

3 years ago