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3 years ago

Plot a point on the coordinate plane to represent each of the ratio values in the table.

Mathematics

1 answer:

Crank3 years ago

5 0

Answer:

U almost got it right I posted the right answer below.

Step-by-step explanation:

The answer should be like this:

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A square has the side measurement of s=6^3/2 , Use the formula A = s^2 , find the area of the square

irakobra [83]

$s=6^{ \frac{3}{2} } \\ \\ A=s^2={(6^{ \frac{3}{2} } )}^2=6^{ 3}= 216 \ \ units^2$

7 0

3 years ago

Customers arrivals at a checkout counter in a department store per hour have a Poisson distribution with parameter λ = 7. Calcul

IgorLugansk [536]

Answer:

(1)14.9% (2) 2.96% (3) 97.04%

Step-by-step explanation:

Formula for Poisson distribution: $P(k) = \frac{\lambda^ke^{-k}}{k!}$ where k is a number of guests coming in at a particular hour period.

(1) We can substitute k = 7 and $\lambda = 7$ into the formula:

$P(k=7) = \frac{7^7e^{-7}}{7!}$

$P(k=7) = \frac{823543*0.000911882}{5040} = 0.149 = 14.9\%$

(2)To calculate the probability of maximum 2 customers, we can add up the probability of 0, 1, and 2 customers coming in at a random hours

$P(k\leq2) = P(k=0)+P(k=1)+P(k=2)$

$P(k\leq2) = \frac{7^0e^{-7}}{0!} + \frac{7^1e^{-7}}{1!} + \frac{7^2e^{-7}}{2!}$

$P(k \leq 2) = \frac{0.000911882}{1} + \frac{7*0.000911882}{1} + \frac{49*0.000911882}{2}$

$P(k\leq2) = 0.000911882+0.006383174+0.022341108 \approx 0.0296=2.96\%$

(3) The probability of having at least 3 customers arriving at a random hour would be the probability of having more than 2 customers, which is the invert of probability of having no more than 2 customers. Therefore:

$P(k\geq 3) = P(k>2) = 1 - P(k\leq2) = 1 - 0.0296 = 0.9704 = 97.04\%$

4 0

3 years ago

PLEASE PLEASE HELP

marta [7]

Answer:

Approximately 3 grams left.

Step-by-step explanation:

We will utilize the standard form of an exponential function, given by:

$f(t)=a(r)^t$

In the case of half-life, our rate r will be 1/2. This is because 1/2 or 50% will be left after t half-lives.

Our initial amount a is 185 grams.

So, by substitution, we have:

$\displaystyle f(t)=185\big(\frac{1}{2}\big)^t$

Where f(t) denotes the amount of grams left after t half-lives.

We want to find the amount left after 6 half-lives. Therefore, t = 6. Then using our function, we acquire:

$\displaystyle f(6)=185\big(\frac{1}{2}\big)^6$

Evaluate:

$\displaystyle f(6)=185\big(\frac{1}{64}\big)\approx2.89\approx 3$

So, after six half-lives, there will be approximately 3 grams left.

3 0

3 years ago

What is the equation of the perpendicular bisector of this line segment?

agasfer [191]

X=2

Explanation:
You need to find the midpoint of the segment

-2+6=4
4/2=2

3 0

3 years ago

What is the answer to f(x)=2x^2-14?

Len [333]

Xmin: -10 Xmax: 10

Ymin: -10 Ymax: 10

4 0

3 years ago