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S_A_V [24]
3 years ago
14

The heights, in inches, of several seventh-grade students at Evan Mills Middle School are

Mathematics
1 answer:
Softa [21]3 years ago
8 0
No sé pero lo investigaré y te ayudaré ahora mismo
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Write the equation of the trigonometric graph.
prisoha [69]

Answer:

f(x)= \sin(6x)+3

Step-by-step explanation:

The parent function of this graph is:  y = sin(x)

The sine function is periodic, meaning it repeats forever.

Standard form of a sine function:

f(x) = \sf A \sin (B(x + C)) + D

  • A = amplitude (height from the mid-line to the peak)
  • 2π/B = period (horizontal distance between consecutive peaks)
  • C = phase shift (horizontal shift - positive is to the left)
  • D = vertical shift

The parent function y = sin(x) has the following:

  • Amplitude (A) = 1
  • Period = 2π
  • Phase shift (C) = 0
  • Vertical shift (D) = 0
  • Mid-line:  y = 0

From inspection of the given graph:

  • Amplitude (A) = 1
  • \sf Period=\dfrac{\pi}{12}-\dfrac{-\pi}{4}=\dfrac{\pi}{3}
  • Phase shift (C) = 0
  • Vertical shift (D) = +3  (as mid-line is y = 3)

\sf If\:Period=\dfrac{\pi}{3} \implies \dfrac{2 \pi}{B}=\dfrac{\pi}{3}\implies B=6

Substituting the values into the standard form:

\implies f(x) =1 \sin (6(x + 0)) + 3

\implies f(x) = \sin (6x) + 3

Therefore, the equation of the given trigonometric graph is:

f(x)= \sin(6x)+3

6 0
2 years ago
5x – 2x + 3x is equal to ?
Cloud [144]

Answer:

4x

Step-by-step explanation:

5x+2x=7x

7x-3x=4x

3 0
3 years ago
Read 2 more answers
In an isosceles triangle, if a base angle has a measure of 43 degrees, then the vertex angle must have a measure of 80 degrees a
tankabanditka [31]
 number one is false and n number two is true
7 0
3 years ago
A student multiplied the two polynomials below. Find the Errors:
SIZIF [17.4K]

second one is correct    

Step-by-step explanation:

6 0
3 years ago
Math:<br> Please help me I don’t understand and I need to do corrections.
GREYUIT [131]
So, you had done everything right so far (other than squaring the 2), but that was only half of the question.

to find the least common multiple, you need to first figure out what the prime factors have in common.
{2}^{2}  \times 3 \times 5 \\ and \\  {2}^{2}  \times  {3}^{2}  \times 5 \times 7
each have two twos. both have one 5, so we know our answer will look something like
{2}^{2}  \times 5 \times other \: stuff
now to figure out the other stuff... we have to represent the greatest amount of everything that is left, and we have 3s and 7s left over, so we need to figure out how many of each we need.

one has one 3 and one has two, so we need two threes. now our equation is
{2}^{2}  \times {3}^{2}  \times 5 \times stuff

what's the only number we have to deal with? 7...

how many sevens does 60 have? 0, and 630 has 1, so we know we need one 7. our answer becomes
4 0
3 years ago
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