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fredd [130]
3 years ago
12

A chicken traveled 4.5 miles in 30 minutes A squirel traveled 4 miles in 20 minutes

Mathematics
1 answer:
Ugo [173]3 years ago
4 0

Answer:

the squirel

Step-by-step explanation:

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A total of 348 tickets were sold for the school play. They were either adult tickets or student tickets. The number of student t
maw [93]
Lets say y is number of adult tickets and x is number of student tickets x+y=348 2x+y=348 (2x since I know that the student tickets are twice as much as adult tickets) I now know that that student tickets make up 2/3 of the total number of tickets and 1/3 make up the number of adults tickets. So... 1/3 x 348= 116 adult tickets 2/3 x 348=232 student tickets
3 0
3 years ago
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BRAINLIEST ANSWER !!!!!!!! Please help me guys if apprieciate it
kari74 [83]

Answer:

i think it is b


Step-by-step explanation:


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3 years ago
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The amount of time that a 4th grader reads comic books in a week is normally distributed with a mean of 6 hours and a standard d
KATRIN_1 [288]

Answer:

0.9544 = 95.44% probability that the sample mean time for reading comic books per week is between 5 and 7 hours.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\mu = 6, \sigma = 2, n = 16, s = \frac{2}{\sqrt{16}} = 0.5

What is the probability that the sample mean time for reading comic books per week is between 5 and 7 hours

This is the pvalue of Z when X = 7 subtracted by the pvalue of Z when X = 5. So

X = 7

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{7 - 6}{0.5}

Z = 2

Z = 2 has a pvalue of 0.9772

X = 5

Z = \frac{X - \mu}{s}

Z = \frac{5 - 6}{0.5}

Z = -2

Z = -2 has a pvalue of 0.0228

0.9772 - 0.0228 = 0.9544

0.9544 = 95.44% probability that the sample mean time for reading comic books per week is between 5 and 7 hours.

6 0
3 years ago
the function f(t)= 3,500(1.003)^t gives the value of a saving account t months after it was opened.How long will it take for the
Pavel [41]

Answer:

After 19 months,value in the account will reach $3700

Step-by-step explanation:

The value of a savings account f(t) in terms of t ( number of months since account opening) is given as \[3,500(1.003)^{t}\]

We need to determine the value of t when f(t)>=3700

Expressing it in equation form,

\[3,500(1.003)^{t} >= 3700\]

\[=>(1.003)^{t} >= \frac{3700}{3500}\]

\[=>(1.003)^{t} >= 1.057\]

Taking log of both sides,

\[=>t * log(1.003) >= log(1.057)\]

\[=>t >= \frac{log(1.057)}{log(1.003)}\]

\[=>t >= 18.51\]

So t = 19.

6 0
3 years ago
If JM = 5x – 8 and LM = 2x – 6, which expression represents JL?
Helga [31]

Answer:

5x-8=2x-6

Step-by-step explanation:

It’s a property but I forgot which one.

6 0
3 years ago
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