Answer: Approximately 30.4 degrees
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Work Shown:
324 - 1.6 = 322.4 is the height of the right triangle. This is the opposite side compared to the angle theta.
The adjacent side is 550 since it is the leg closest to the angle theta.
We'll use the tangent rule to connect the two sides
tan(angle) = opposite/adjacent
tan(theta) = 322.4/550
theta = arctan(322.4/550)
theta = 30.3780566013696
theta = 30.4
Your teacher didn't provide any rounding instructions, but I rounded to one decimal place since the value 1.6 is to one decimal place.
Answer:
(a) The unit of 70.5 is lbm/ft^3 and the unit of 8.27×10^-7 is in^2/lbf
(b) density = 0.1206g/cm^3
(c) rho = 0.1206exp(8.27×10^-7P)
Step-by-step explanation:
(a) The unit of 70.5 is the same as the unit of rho which is lbm/ft^3. The unit of 8.27×10^-7 is the inverse of the unit of P (lbf/in^2) because exp is found of a constant. Therefore, the unit of 8.27×10^-7 is in^2/lbf
(b) P = 9×10^6N/m^2
rho = 70.5exp(8.27×10^-7× 9×10^6) = 70.5exp7.443 = 70.5×1.71 = 120.6kg/m^3
rho = 120.6kg/m^3 × 1000g/1kg × 1m^3/10^6cm^3 = 0.1206g/cm^3
(c) Formula for rho (g/cm^3) as a function of P (N/m^2) is
rho = 0.1206exp(8.27×10^-7P) (the unit of 0.1206 is g/cm^3)
Answer:
D
Step-by-step explanation:
We can safely assume we are dealing with an arithmetic scale because the type of scale isn't mentioned anywhere. The more right a point is on the scale, the higher its value is. We are given two points of the scale: 3 and 4. Because the scale is arithmetic, we know that 3.8 must lie on 4/5s of the length between 3 and 4 to the right of 3, which is exactly where point D is.
Answer:
64 cm^2
Step-by-step explanation:
Square: 4*4 = 16
Triangles: 4((4*6)/2))
= 4(24/2)
= 4(12)
= 48
Add the square and triangles together
= 16 + 48
= 64
The total will be 64 cm^2
Answer: The correct option is, The coefficient of the first term.
Step-by-step explanation:
The given function is,
End behavior of the polynomial function : It is defined as the graph of f(x) as x approaches 
and 
.
The end behavior of the graph depends on the leading coefficient and degree of the polynomial.
As, the degree of the polynomial is '3'. So, the leading coefficient will determine the structure of the graph.
Therefore, the coefficient of the first term will indicate that the left end starts at the top of the graph.
The graph is also shown below.
