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3 years ago

What are common work activities performed by Veterinarians?

SAT

2 answers:

valentinak56 [21]3 years ago

7 0

Answer:

Advising clients on care of their pets

Administering immunizations

Conducting physical examinations

Providing emergency care

Explanation:

Delicious77 [7]3 years ago

3 0

Examine animals to diagnose their health problems.
Treat and dress wounds.
Perform surgery on animals.
Test for and vaccinate against diseases.
Operate medical equipment such as x-ray machines.
Advise animal owners about general care, medical conditions, and treatments.

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On kyle thomason's $400,000. 00 loan, the lender charges a 2-point service charge. In this situation, how much will kyle have to

AnnyKZ [126]

Answer: sorry the correct answer is $8,000

Explanation:400,000 x .2% =$8.000 debit to the buyer

4 0

2 years ago

Find δs o for the combustion of methane to carbon dioxide and liquid water.

mote1985 [20]

The entropy change ΔS for the combustion of methane to carbon dioxide and liquid water is -242.6 J/mol.K

<h3>What is the Entropy in a Chemical system?</h3>

In a chemical system, Entropy (ΔS) is a quantitative measure of the variety of possible ways to disperse energy inside a chemical system.

In an isothermal process, entropy is determined as the quantity of heat transmitted to a system.

The chemical reaction for the combustion of methane can be expressed as:

$\mathbf{CH_{4(g)} + 2O_{2(g)} \to CO_{2(g)} + 2H_2O_{(l)}}$

The standard entropy of the combustion is expressed as:

$\mathbf{\Delta S^0 =(S^0 _{CO_{2}} + 2 \times S^0 _{H_{2}O} )+(-S^0 _{CH_{4}} -2 \times S^0 _{O_{2}} })$

Replacing the standard entropies of the compounds into the above equation, we have:

$\mathbf{\Delta S^0 =(213.8 \8 \ J/mol.K + 2 \times69.92 \ J/mol.K )+(-186.16 \ J/mol.K -2 \times 205.04 \ J/mol.K})$

$\mathbf{\Delta S^0 =-242.6 \ J/mol.K}$

Learn more about entropy here:

brainly.com/question/6364271

6 0

2 years ago

Frank, who lives in texas, and his sister lilly, who lives in japan, correspond regularly. From what he can tell from the postma

ehidna [41]

Answer:

(A) There is convincing evidence that there is no difference in the mean delivery times.

(B) There is convincing evidence that there is a difference in the mean delivery times.

(C) There is convincing evidence that the mean delivery time from Japan to Texas is greater than the mean delivery time from Texas to Japan.

(D) There is not convincing evidence that the mean delivery time from Japan to Texas is greater than the mean delivery time from Texas to Japan.

(E) The t-test cannot be used for sample sizes that are this small.

Explanation:

The correct option is;

(A) There is convincing evidence that there is no difference in the mean delivery times.

Step-by-step explanation:

Here we have the formula for the two-sample t-test given s;

To Texas N₁ = 12, =8.74 σ₁ = 2.92 SE Mean₁ = 0.84

To Japan N₂ = 9 = 6.75 σ₂ = 2.56 SE Mean₁ = 0.85

t = 1.667

Where the null hypothesis is

mu To Texas = mu To Japan and the alternative is

mu To Texas > mu To Japan

Here since the observed P value of P = 0.058 is greater than the significance level of 0.05 we fail to reject the null hypothesis and we will therefore, not accept the alternative hypothesis.

Hence, there is convincing evidence that there is no difference in the mean delivery times.

3 0

2 years ago

Is observation a useful tool to help teachers decide what to do next when planning lesson/activities for children?

Mice21 [21]

Answer:

Yes

Explanation:

In this way both children and teachers can understand clearly and decide... What to do next..

Hope it helped u if yes mark me BRAINLIEST!

Tysm!

7 0

3 years ago

*SAT QUESTION*

denis23 [38]

Answer and Explanation:

$Greetings!$

$Let's~answer~your~question!$

$Triangle~ ABC ~is ~a ~right~ triangle~ with ~its~ right~ angle ~at ~B. ~Therefore,~AC\\is~ the~ hypotenuse~ of~ right~ triangle~ ABC,~ and~ AB ~and ~BC ~are~ the~ legs~ of~ right~\\ triangle ~ABC.$

$According~ to~ the~ Pythagorean ~theorem,$

$AB=\sqrt{20^2-16^2}=\sqrt{400-256}=\sqrt{144}=12$

$Since ~triangle~DE$ $F~is ~similar~ to~ triangle~ ABC,~ with~ vertex ~F ~corresponding~to~ vertex~ C,~ the~ measure\\ of~angle~ \angle F~equals~ the~ measure~ of~ angle~\angle C.$

$Therefore,~ sinF=sinC. ~From ~the~ side~ lengths~ of ~triangle~ ABC,$

$sinF=\frac{opposite ~side}{hypotenuse} =\frac{AB}{AC} =\frac{12}{20}=\frac{3}{5}$

$Therfore, ~sinF=\frac{3}{5}~or~0.6$

3 0

3 years ago

Read 2 more answers