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Rudiy27
3 years ago
13

Geometry triangles ​

Mathematics
2 answers:
Oliga [24]3 years ago
7 0
Where are the questions?
aleksandrvk [35]3 years ago
6 0
Do you have a question?
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-34 + 91 = -3 (4x + 1) + 6x
ra1l [238]

-34 + 91 = -3(4x+1) + 6x\\57 = -12x - 3 + 6x\\6x = -60\\x= -10\\

Thus x = -10.

Hope that helps!

3 0
3 years ago
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In the diagram which angle is part of a linear pair and part of a vertical pair
yulyashka [42]

Answer:

d. < EFA

Step-by-step explanation:

6 0
3 years ago
Max caught 43 lb of fish in one deep sea fishing trip the fish needed to be equally separated by weight into 5 packages to sell
solmaris [256]
43÷5=8.6   he would put 8.6 lb per bag
6 0
4 years ago
PLZ help thnx
Pepsi [2]

Answer:

A) $40

B) 40M = P

C)  $3,120

Step-by-step explanation:

Given that at her salon, last week Tammy did 25 manicures and collected $ 1000, to calculate the slope to represent the manicures, write an equation to represent this relation and determine how much would Tammy make if she did 78 manicures in a month the following calculations should be performed:

A)

1000/25 = X

40 = X

Thus, each manicure costs $ 40.

B)

40M = P

C)

78 x 40 = X

3.120 = X

So if she did 78 manicures in a month, Tammy would earn $ 3,120.

8 0
3 years ago
Arrange these functions from the greatest to the least value based on the average rate of change in the specified interval.
Romashka [77]
By definition, the average change of rate is given by:
 AVR =  \frac{f(x2)-f(x1)}{x2-x1}
 We will calculate AVR for each of the functions.
 We have then:

 f(x) = x^2 + 3x interval: [-2, 3]:
 f(-2) = x^2 + 3x  = (-2)^2 + 3(-2) = 4 - 6 = -2&#10;&#10;f(3) = x^2 + 3x = (3)^2 + 3(3) = 9 + 9 = 18
 AVR = \frac{-2-18}{-2-3}
 AVR = \frac{-20}{-5}
 AVR = 4

 f(x) = 3x - 8 interval: [4, 5]:
 f(4) = 3(4) - 8 = 12 - 8 = 4 f(5) = 3(5) - 8 = 15 - 8 = 7
 AVR = \frac{7-4}{5-4}
 AVR = \frac{3}{1}
 AVR = 3

 f(x) = x^2 - 2x interval: [-3, 4]
 f(-3) = (-3)^2 - 2(-3) = 9 + 6 = 15&#10;&#10;f(4) = (4)^2 - 2(4) = 16 - 8 = 8
 AVR = \frac{8-15}{4+3}
 AVR = \frac{-7}{7}
 AVR = -1

 f(x) = x^2 - 5 interval: [-1, 1]
 f(-1) = (-1)^2 - 5 = 1 - 5 = -4&#10;&#10;f(1) = (1)^2 - 5 = 1 - 5 = -4
 AVR = \frac{-4+4}{1+1}
 AVR = \frac{0}{2}
 AVR = 0


 Answer:
 
these functions from the greatest to the least value based on the average rate of change are:
 f(x) = x^2 + 3x
 
f(x) = 3x - 8
 
f(x) = x^2 - 5
 
f(x) = x^2 - 2x
5 0
3 years ago
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