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arlik [135]
3 years ago
15

O is the center of both circles containing arcs AB and CD

Mathematics
1 answer:
victus00 [196]3 years ago
5 0

Answer:

Step-by-step explanation:

You need to solve the area sector of the bigger circle. Since we now the length of sector is 270, we can set up an equation.  

Length of sector DC = 2\pir

270 = 2\pi(8+OA)                     *(8+OA is the raidus of the bigger circle/sector)*

270/2\pi = 8 + OA  (division)

135/\pi -8 = OA

135/\pi -8 = OB (because OA and OB are the raidus of the same circle, so they are congruent)

I hope this helps you! Please correct me if you see a miscalculation <3<3

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igomit [66]
Just multiply the top number by the top number and the bottom numbers by the bottom numbers so


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3 years ago
Read 2 more answers
Use a half-angle identity to find the exact value
Tatiana [17]

Given:

\cos 15^{\circ}

To find:

The exact value of cos 15°.

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$\cos 15^{\circ}=\cos\frac{ 30^{\circ}}{2}

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$\cos \left(\frac{x}{2}\right)=\sqrt{\frac{1+\cos (x)}{2}}

$\cos \frac{30^{\circ}}{2}=\sqrt{\frac{1+\cos \left(30^{\circ}\right)}{2}}

Using the trigonometric identity: \cos \left(30^{\circ}\right)=\frac{\sqrt{3}}{2}

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Let us first solve the fraction in the numerator.

            $=\sqrt{\frac{\frac{2+\sqrt{3}}{2}}{2}}

Using fraction rule: \frac{\frac{a}{b} }{c}=\frac{a}{b \cdot c}

            $=\sqrt{\frac {2+\sqrt{3}}{4}}

Apply radical rule: \sqrt[n]{\frac{a}{b}}=\frac{\sqrt[n]{a}}{\sqrt[n]{b}}

           $=\frac{\sqrt{2+\sqrt{3}}}{\sqrt{4}}

Using \sqrt{4} =2:

           $=\frac{\sqrt{2+\sqrt{3}}}{2}

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3 years ago
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Ivahew [28]

Answer: you can find the area of a circle by multiplying the radius by pi and then squaring it by 2

Step-by-step explanation:

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2 years ago
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