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3 years ago

O is the center of both circles containing arcs AB and CD

Mathematics

1 answer:

victus00 [196]3 years ago

5 0

Answer:

Step-by-step explanation:

You need to solve the area sector of the bigger circle. Since we now the length of sector is 270, we can set up an equation.

Length of sector DC = 2 $\pi$ r

270 = 2 $\pi$ (8+OA) *(8+OA is the raidus of the bigger circle/sector)*

270/2 $\pi$ = 8 + OA (division)

135/ $\pi$ -8 = OA

135/ $\pi$ -8 = OB (because OA and OB are the raidus of the same circle, so they are congruent)

I hope this helps you! Please correct me if you see a miscalculation <3<3

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3 years ago

What type of object is generated when you rotate a 2-dimensional object about an axis?

dalvyx [7]

A three-dimensional object

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3 years ago

Geometry page 1 help please !

victus00 [196]

Answer:

16) $y=\frac{1}{4}x +5$

17) y = -x - 4

18) y = -2x - 1

19) y = -2x

20) $y=\frac{-5}{3} -3$

Step-by-step explanation:

With the two points you find the slope using $\frac{y_{2}-y_{1} }{x_{2}-x_{1} }$

Then using that slope, plug the slope in with one of the points values of x and y into the point slope formula, and smiplify that into the y-intercept formula.

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3 years ago

You cut a circular hole 1/4 -inch in diameter in a piece of cardboard. With the cardboard 30 inches from your face, the Moon fit

Stolb23 [73]

Answer:

The Moon's diameter is greater than $1,500$ miles

Step-by-step explanation:

we know that

$1\ mile=63,360\ inches$

$1,500\ miles=1,500*63,360=95,040,000\ inches$

$240,000\ miles=240,000*63,360=15,206,400,000\ inches$

by proportion

Find the Moon's diameter

Let

x-----> the Moon's diameter in inches

$\frac{x}{15,206,400,000}=\frac{0.25}{30}\\ \\x= 15,206,400,000*0.25/30\\ \\x=126,720,000\ inches$

Compare

$126,720,000\ inches> 95,040,000\ inches$

therefore

The Moon's diameter is greater than $1,500$ miles

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3 years ago

Evaluate the expression -7 1/4x + 3 5/8 for x= -4

Misha Larkins [42]

Answer:

32 5/8 (or 32 and 5/8)

Step-by-step explanation:

Okay, so this problem is asking for us to solve this problem with the substitution of a variable: x = -4. Before we fully solve this problem, we need to replace all of those x variables with -4 so that it is easier to solve.

-7 1/4(-4) + 3 5/8.

To make this problem even easier to solve, let's turn these mixed numbers into improper fractions. To do this, multiply the denominator by the whole number. Then add the numerator to this number. The new number that you just got is now your new numerator for this number.

-29/4(-4) + 3 5/8.

Repeat the last step to turn the other mixed number into an improper fraction.

-29/4(-4) + 29/8.

Now let's multiply that -4 by 29/4. Because a whole number technically has a denominator of 1, we can now set up the next part of our problem. (The symbol * means multiplication since we can't use x since it is already being used as a variable in this equation.)

(-29/4 * -4/1) + 29/8.

29 + 29/8.

Now to solve the rest of this problem, let's convert the whole number of 29 so that it has a denominator of 8. This is that these two numbers are addable.

29 x 8 = 232

1 x 8 = 8

Now these numbers are addable. So:

232/8 + 29/8 = 261/8 = 32 5/8.

I hope that this helps.

4 0

3 years ago