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arlik [135]
2 years ago
15

O is the center of both circles containing arcs AB and CD

Mathematics
1 answer:
victus00 [196]2 years ago
5 0

Answer:

Step-by-step explanation:

You need to solve the area sector of the bigger circle. Since we now the length of sector is 270, we can set up an equation.  

Length of sector DC = 2\pir

270 = 2\pi(8+OA)                     *(8+OA is the raidus of the bigger circle/sector)*

270/2\pi = 8 + OA  (division)

135/\pi -8 = OA

135/\pi -8 = OB (because OA and OB are the raidus of the same circle, so they are congruent)

I hope this helps you! Please correct me if you see a miscalculation <3<3

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What is the answer to (-2)^3-2^3
ANEK [815]
Approaching algebraicly(Take 2 as x)
(-x)^3-x^3
Simplify
Result is -2x^3
Put back 2
-2(2)^3 = -2(8)
= -16
6 0
3 years ago
WILL GIVE BRAINLIEST!
expeople1 [14]

Answer:

Average\:Rate\:Change=-59.4

Step-by-step explanation:

The given function is f(x)=120(0.1)^x.


We want to find the average rate of change of this function from x=0 to x=2.


This is given by:

Average\:Rate\:Change=\frac{f(2)-f(0)}{2-0}


This implies that;


Average\:Rate\:Change=\frac{120(0.1)^2-120(0.1)^0}{2-0}


Average\:Rate\:Change=\frac{120(0.1)^2-120}{2}


Average\:Rate\:Change=\frac{120((0.1)^2-1)}{2}


Average\:Rate\:Change=\frac{60(0.01-1)}{1}


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5 0
3 years ago
QUESTION 20
atroni [7]

.Answer:

The answer is below

Step-by-step explanation:

The patient loses 1 kg every week for 5 weeks.

1 kg = 2.2 lbs

Therefore the patient loses 2.2 lbs every week for 5 weeks.

a) The weight of the patient after 5 weeks = 245 lbs. - (5 weeks)(2.2 lbs per week)

The weight of the patient after 5 weeks = 245 lbs. - 11 lbs. = 234 lbs.

b) The weight of the patient after 5 weeks = 245 lbs. - 11 lbs. = 234 lbs.

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7 0
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A number divided by three less two is at most two
Marina CMI [18]

x ≤ 12

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Let us take the number be x.

A number : x

A number divided by three : $\frac{x}{3}

A number divided by three less two : $\frac{x}{3}-2

A number divided by three less two is at most two : $\frac{x}{3}-2\leq 2

Now, simplify the inequality,

$\Rightarrow\frac{x}{3}-2\leq 2

Add 2 on both sides of the inequality,

$\Rightarrow\frac{x}{3}-2+2\leq 2+2

$\Rightarrow\frac{x}{3}\leq 4

Multiply by 3 on both sides of the equation,

$\Rightarrow\frac{x}{3}\times3\leq 4\times3

$\Rightarrow x\leq 12

Hence x ≤ 12.

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3 years ago
Is 0.245245245... a rational or irrational number?
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It is Irrational because is can not be written as a fraction
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3 years ago
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