1 pencil + 1 eraser = $1.10
Pencil cost $1 more than the eraser.
⇒ If we take away $1 from the total, both the pencil and the eraser will cost the same.
⇒ $1.10 - $1.00 = $0.10
Divide by 2 to find the cost of the eraser.
⇒$0.10 ÷ 2 = $0.05
Find the cost of the pencil, which is $1 more than the eraser.
⇒ $0.05 + $1 = $1.05
Answer: The eraser costs $0.05
Answer: The net weight of the pigs of the truck is 1 ton 868 pounds 12 ounces.
The weight of the empty truck is 7 tons 254 pounds 10 ounces.
Step-by-step explanation:
Since we have given that
The gross weight of a truck containing 30 pigs = 8 tons 1123 pounds 6 ounces
Average weight of one pig = 95 pounds 10 ounces
Now,
We know that
So,
Similarly,
So, Net weight of the pigs in the truck
So, the net weight of the pigs of the truck is 1 ton 868 pounds 12 ounces.
Now, we'll find the weight of the empty truck is given by
Hence, the weight of the empty truck is 7 tons 254 pounds 10 ounces .
M(month)*g(amount of games)=x(how many games sold in a month)
16•0.10= 1.60$
8•0.05= 0.40¢
12•0.25= 3.00$
1.60$+0.40¢+3.00$= 5.00$
3•0.10= 0.30¢
5•0.05= 0.25¢
0.30¢+0.25¢= 0.55¢
5.00$-0.55¢= 4.45$
4.45$ is left in the piggy bank.
The solution to the problem is as follows:
x^3-x^2 +x -1= x^2(x-1) +(x-1)=(x-1)(x^2+1) ,(common factor x-1
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(x^2-1)=(x-1)(x+1) </span>
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LCM=(x-1)(x^2+1)(x+1) </span>
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=(x^2-1)(x^2+1)=x^4-1
I hope my answer has come to your help. God bless and have a nice day ahead!
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