Hello from MrBillDoesMath!
Answer:
The third choice, 99
Discussion:
I'm not sure what that strange cutout in the parallelogram has to do with the problem but ..... the area of parallelogram is given by (base)(height). In our case, assuming the length ("height') ED = 11 and length AB ("base") = 5 + 4 = 9, the area = 11 * 9 = 99 square centimeter. This is the third choice.
Thank you,
MrB
Answer:
k = 10
Step-by-step explanation:
The sum of k terms of a geometric sequence with first term a1 and common ratio r is given by ...
... Sk = a1·(1 -r^k)/(1 -r)
For the given numbers, this is ...
... 118096 = 78732·(1 -(1/3)^k)/(1 -1/3)
Manipulating this to get the term containing k, we have
... 1 -(2/3)(118096/78732) = (1/3)^k
... 1/59049 = (1/3)^k
Taking logarithms, we get
... -log(59049) = -k·log(3)
... log(59049)/log(3) = k = 10
Answer:
PQ = 16
Step-by-step explanation:
Using the cosine ratio in the right triangle and the exact value
cos60° = 
, then
cos60° = 
= 
= 
= ( cross- multiply )
PQ = 8 × 2 = 16
Answer:
2880
Step-by-step explanation:
V=whl=12·12·20=2880
Answer:
base of the triangle = 12 m
Explanation:
Area of the triangle = 1/2 * base * height
We are given that:
area = 54 m^2
height = 9 m
Substitute in the equation to get the base as follows:
Area of the triangle = 1/2 * base * height
54 = 1/2 * base * 9
108 = 9*base
base = 12 m
Hope this helps :)
