Question

I was wondering if someone can please help me I keep getting the wrong answer and I was just wondering if someone could explain it and help me

Answer 1

Answer:

$h(g(-5)) = 127$

Explanation:

Given

$h(x) = 2x^2 - 1$

$g(x) = x - 3$

Required

Find $h(g(-5))$

First, we need to solve for $g(-5)$

$g(x) = x - 3$

Substitute -5 for x

$g(-5) = -5 - 3$

$g(-5) = -8$

Substitute -8 for g(-5) in $h(g(-5))$

$h(g(-5))$ = $h(-8)$

Given that:

$h(x) = 2x^2 - 1$

Substitute -8 for x

$h(-8) = 2(-8)^2 - 1$

$h(-8) = 2*64 - 1$

$h(-8) = 128 - 1$

$h(-8) = 127$

Hence:

$h(g(-5)) = 127$