4(2x + 10)=0
8x + 40 = 0
8x = -40
x = -5
Answer:
i am good so nah but free pionts tanks
Step-by-step explanation:
Answer:
<h2>m∠ACE = 90°</h2>
Step-by-step explanation:
Figure Interpretation:
m∠CBA + m∠CDE = 180
m∠BCA = (180-m∠CBA)/2
m∠DCE = (180-m∠CDE)/2
=======================
Then
m∠BCA + m∠DCE = (180-m∠CBA)/2 + (180-m∠CDE)/2
= [360-(m∠CBA+m∠CDE)]/2
= [360 - 180]/2
= 90
finally,
m∠ACE= 180 - (m∠BCA + m∠DCE)
= 180 - 90
= 90
The answer is B.
Hope that helped! :)
<span>let x = the original no. of students
then
(x+10) = the actual no. that went on the trip
:
= the original cost per student
and
= the actual cost
:
Original cost - actual cost = $12.50
- = 12.50
multiply equation by x(x+10)
x(x+10)* - x(x+10)* = 12.50x(x+10)
Cancel the denominators
1500(x+10) - 1500x = 12.5x(x+10)
1500x + 15000 - 1500x = 12.5x^2 + 125x
Combine on the right to form a quadratic equation
0 = 12.5x^2 + 125x - 15000
Simplify, divide equation by 12.5
x^2 + 10x - 1200 = 0
You can use the quadratic formula; a=1; b=10; c=-1200, but this will factor to
(x + 40(x - 30) = 0
The positive solution is what we want here
x = 30 students in the original group
Check this by finding the cost per student for each scenario
1500/30 = $50.00; original cost
1500/40 = $37.50; actual cost
---------------------
saving: $12.50</span>
