5(-4)+22 = (-4)+6
-20+22 = -4+6
2 = 2
Maria is correct, since both sides equally match.
The rule to remember for this problem is: i^2 = -1
(4 + i)(1 - 5i)
4 - 20i + i - 5i^2
4 - 19i + 5
9 - 19i
For the first one it is x=1 the second one X=8
Answer:
The real solution is 
.
Step-by-step explanation:
while 
So the equation becomes:
We know that 
. So let's see what gives us:
.
is the result we wanted.
is therefore a solution.
U = ( -8 , -8)
v = (-1 , 2 )
<span>the magnitude of vector projection of u onto v =
</span><span>dot product of u and v over the magnitude of v = (u . v )/ ll v ll
</span>
<span>ll v ll = √(-1² + 2²) = √5
</span>
u . v = ( -8 , -8) . ( -1 , 2) = -8*-1+2*-8 = -8
∴ <span>(u . v )/ ll v ll = -8/√5</span>
∴ the vector projection of u onto v = [(u . v )/ ll v ll] * [<span>v/ ll v ll]
</span>
<span> = [-8/√5] * (-1,2)/√5 = ( 8/5 , -16/5 )
</span>
The other orthogonal component = u - ( 8/5 , -16/5 )
= (-8 , -8 ) - <span> ( 8/5 , -16/5 ) = (-48/5 , -24/5 )
</span>
So, u <span>as a sum of two orthogonal vectors will be
</span>
u = ( 8/5 , -16/5 ) + <span>(-48/5 , -24/5 )</span>
