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victus00 [196]
2 years ago
12

Tomen puntos toy aburridoooo​

Mathematics
2 answers:
ivanzaharov [21]2 years ago
6 0

Answer:

aww thank you

pls mark brainliest

Step-by-step explanation:

Basile [38]2 years ago
3 0

Answer:

same

Step-by-step explanation:

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Pls help I’m failing I’ll brainlest
LenKa [72]

Answer:

6x

Step-by-step explanation:

Since 2 sides are equal to 3x-3, multiply 3x-3 by 2.

=6x-6

Subtract 18x+6 - 6x-6

= 12x

Since 2 there are 2 sides missing, 12x divided by 2

=6x

7 0
2 years ago
If r(x) = 3x - 1 and s(x) = 2x + 1, which expression is equivalent to (r/s)(6)?
Nana76 [90]

Answer:

Step-by-step explanation:

(r/s)(x) is the quotien of r(x) = 3x - 1 and s(x) = 2x + 1:

  r            3x - 1

(-----)(x) = ----------

  s            2x + 1

8 0
2 years ago
Simplify the given algebraic expression.<br> 8(5y - 8) - (5y + 3)
RoseWind [281]

Answer:

35y - 67

Step-by-step explanation:

8(5y - 8) - (5y + 3)

Multiply the 8 with what is in the parentheses.

40y - 64 - 5y + 3

Subtract like terms.

35y - 67

7 0
2 years ago
Read 2 more answers
Find all roots: x^3-7x^2-12x = 0
Pepsi [2]

Answer:

The roots are  0, 3 and 4.

Step-by-step explanation:

x^3-7x^2-12x = 0   Take out x:

x(x^2 - 7x - 12) = 0  Factor the expression in the brackets:

x(x - 3)(x - 4) = 0

x = 0 or x - 3 = 0 or x - 4 = 0, so

The roots are  0, 3 and 4.

5 0
2 years ago
What is the directrix of the parabola defined by `(1)/(4)(y + 3) = (x − 2)^2`?
Sauron [17]

The directrix of the parabola is y =  \frac {-49}{16}

<h3>How to determine the equation of the directrix?</h3>

The parabola equation is given as:

\frac 14(y + 3) = (x -2)^2

A parabola is represented as:

4p(y - k) =(x -h)^2

By comparing both equations, we have:

4p = 1/4 ==> p = 1/16

-k= 3 ==> k = -3

The directrix is represented as:

y = k - p

So, we have:

y = -3 - \frac 1{16}

Take the LCM

y =  \frac {-16 * 3- 1}{16}

Evaluate

y =  \frac {-49}{16}

Hence, the directrix of the parabola is y =  \frac {-49}{16}

Read more about parabola at:

brainly.com/question/1480401

#SPJ1

4 0
1 year ago
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