Answer:
The answer is A(-3,-4) B(-1,2) C(2,1) D(0,-5)
Step-by-step explanation:
Answer: number 3 4 5
Step-by-step explanation:hope this helps!
Answer: 0.0793
Step-by-step explanation:
Let the IQ of the educated adults be X then;
Assume X follows a normal distribution with mean 118 and standard deviation of 20.
This is a sampling question with sample size, n =200
To find the probability that the sample mean IQ is greater than 120:
P(X > 120) = 1 - P(X < 120)
Standardize the mean IQ using the sampling formula : Z = (X - μ) / σ/sqrt n
Where; X = sample mean IQ; μ =population mean IQ; σ = population standard deviation and n = sample size
Therefore, P(X>120) = 1 - P(Z < (120 - 118)/20/sqrt 200)
= 1 - P(Z< 1.41)
The P(Z<1.41) can then be obtained from the Z tables and the value is 0.9207
Thus; P(X< 120) = 1 - 0.9207
= 0.0793
Answer:
The answer is 150
Step-by-step explanation:
I think what you mean with the numbers between the "I's" is <em>absolute value</em>. Any number is just that number, so the <em>absolute value </em>of -6, is 6. The absolute value of 24 is 24. That means it's simply 137+13, which is <u>150</u>.
