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3 years ago

How do you do this (move 3 circles to make the figure upside down

Mathematics

1 answer:

velikii [3]3 years ago

8 0

Answer:

Move the top left and right to the sides of the second to last row, then move the single circle from the bottom row to the top.

Step-by-step explanation:

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Find the m please it’s due today . (-11,5) & (2,-4)

d1i1m1o1n [39]

Answer:

m = $\frac{-9}{13}$

Step-by-step explanation:

I'm assuming by m, you mean the slope.

You have two points. (-11, 5) and (2, -4)

m = change in y-value ÷ change in x-value

1) Substitute in the points.

m = $\frac{(-4)- 5}{2 - (-11)}$

2) Solve.

-4 - 5 = -9

2 - (-11) = 13

So, the slope would equal $\frac{-9}{13}$ .

4 0

3 years ago

Will be giving all my points away and giving brainliest so please help me!!

Mars2501 [29]

1. 22: 154 (divide 154 by 22)

1:7

if the figures are similar the ratio's of side lengths must be the same

12:b

multiply 12 by 7 to get side b

b = 84

Choice C

2: 1: 25 is the scale factor

6:tree

we need to multiply by 25

6*25 = 150

Choice C

8 0

4 years ago

Read 2 more answers

Graph a parabola whose x-intercepts are at x = -3 and x = 5 and whose minimum value is y = -4.

shtirl [24]

Answer:

(See explanation and attachment below for further details)

Step-by-step explanation:

The parabola must satisfy the following conditions:

$y + 4 = C\cdot (x - k)^{2}$

$y + 4 = C\cdot (x^{2}-2\cdot k \cdot x + k^{2})$

The expression for the x-intercepts are, respectively:

x = -3

$4 = C\cdot [(-3)^{2} - 2\cdot k\cdot (-3)+k^{2}]$

$\frac{4}{C} = 9 + 6\cdot k + k^{2}$

x = 5

$4 = C\cdot [5^{2}-2\cdot k \cdot (5)+k^{2}]$

$\frac{4}{C} = 25 - 10\cdot k + k^{2}$

By equalizing both expressions:

$9 + 6\cdot k + k^{2} = 25 - 10\cdot k + k^{2}$

$16\cdot k = 16$

$k = 1$

And,

$C = \frac{4}{25-10\cdot (1)+1^{2}}$

$C = \frac{1}{4}$

The equation of parabola is:

$y = \frac{1}{4}\cdot (x-1)^{2} - 4$

Whose graph is included as attachment.

5 0

3 years ago

The population of Canada is 3.5×10^7, and the population of the world is 7.0×10^9. How many times larger is the population of th

Setler [38]

Answer:

The population of the world is 200 times of the population of Canada.

Step-by-step explanation:

Given that,

Canada's population = $3.5\times 10^7$

The population of world = $7.0\times 10^9$

We need to find how many times larger is the population of the world compared to Canada's population. It can be solved as follows :

$\dfrac{W}{C}=\dfrac{7.0\times 10^9}{3.5\times 10^7}\\\\\dfrac{W}{C}=200\\\\W=200C$

So, the population of the world is 200 times of the population of Canada.

3 0

3 years ago

PLEASE HELP I WILL MARK BRAINLIEST!!!!

guapka [62]

Answer:

Math-way

Step-by-step explanation:

I'd do it for you right now if you wanted but it'd be much faster if you did it, It's is perfect for this problem

8 0

3 years ago