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boyakko [2]
3 years ago
12

How to write words to match the expression

Mathematics
1 answer:
miss Akunina [59]3 years ago
5 0
Three plus twelve multiplied by four
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Make w the subject of the formula s = w/a
enot [183]

Answer:

w = sa

Step-by-step explanation:

Given

s = \frac{w}{a} ( multiply both sides by a to clear the fraction )

sa = w

8 0
2 years ago
Tan(2 sin^-1 0.4)<br> Find the Exact value
stiv31 [10]

Answer:

tan(2u)=[4sqrt(21)]/[17]

Step-by-step explanation:

Let u=arcsin(0.4)

tan(2u)=sin(2u)/cos(2u)

tan(2u)=[2sin(u)cos(u)]/[cos^2(u)-sin^2(u)]

If u=arcsin(0.4), then sin(u)=0.4

By the Pythagorean Identity, cos^2(u)+sin^2(u)=1, we have cos^2(u)=1-sin^2(u)=1-(0.4)^2=1-0.16=0.84.

This also implies cos(u)=sqrt(0.84) since cosine is positive.

Plug in values:

tan(2u)=[2(0.4)(sqrt(0.84)]/[0.84-0.16]

tan(2u)=[2(0.4)(sqrt(0.84)]/[0.68]

tan(2u)=[(0.4)(sqrt(0.84)]/[0.34]

tan(2u)=[(40)(sqrt(0.84)]/[34]

tan(2u)=[(20)(sqrt(0.84)]/[17]

Note:

0.84=0.04(21)

So the principal square root of 0.04 is 0.2

Sqrt(0.84)=0.2sqrt(21).

tan(2u)=[(20)(0.2)(sqrt(21)]/[17]

tan(2u)=[(20)(2)sqrt(21)]/[170]

tan(2u)=[(2)(2)sqrt(21)]/[17]

tan(2u)=[4sqrt(21)]/[17]

7 0
3 years ago
a wildlife photographer spent 5 minutes taking pictures of a bison at a park. when the bison then decided she didn't want her ph
ZanzabumX [31]

The percent of time the photographer spent negotiating with the bison greater than the time he spent taking pictures is 500%

<h3>Percentage</h3>

  • Time spent taking pictures = 5 minutes
  • Time spent negotiating = 30 minutes

Percentage of time negotiating greater than taking pictures = (difference in time) / time to take pictures × 100

= (30 - 5) / 5 × 100

= 25/5 × 100

= 5 × 100

= 500%

Learn more about percentage:

brainly.com/question/843074

#SPJ1

4 0
2 years ago
Jacks rent will increase $30 if he pays for $415 now how much will his new rent cost each month
shusha [124]

Jack's rent will increase to $445

5 0
2 years ago
Solve the problem by multiplying first. A clothing store is having a sale on shirts and jeans. Four shirts and two pairs of jean
ella [17]

We will solve this by suing simultaneous equations,

⇒ 5s + 3j = 87

    4s + 2j = 64

Multiply the first equation with 4 and the second one with 5, this is to get one of the values equal so that we can cancel them out,

⇒ (5s + 3j = 87) × 4

    (4s + 2j = 64) × 5

∴ ⇒ 20s + 12j = 348

       20s + 10j = 320

Subtract both the equations. This is how your result (after subtraction) should look like,

  ⇒ 2j = 28

∴ ⇒ j = $14

Now replace the value of 'j' in one of the original equations,

⇒ 4s + 2(14) = 64

⇒ 4s + 28 = 64

⇒ 4s = 64 - 28

⇒ 4s = 36

∴ ⇒ s = $9

Therefore, one pair of jeans cost $14 and a shirt costs $9

Hope you understood! Feel free to ask me if you didn't understand a step.

5 0
2 years ago
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