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makkiz [27]
3 years ago
10

For the function f(x)=3x-4 find f(2)

Mathematics
1 answer:
mr Goodwill [35]3 years ago
4 0

Hi there!

\large\boxed{f(2) = 2}

Evaluate f(x) at x = 2 by substituting 2 for x:

f(x) = 3x - 4

f(2) = 3(2) - 4

f(2) = 6 - 4

f(2) = 2

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Answer:

(1,6)

Step-by-step explanation:

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3 years ago
Read 2 more answers
The 2014 Community College Survey of Student Engagement (CCSSE) included a question that asked faculty how much of their coursew
Kisachek [45]

Answer:

Step-by-step explanation:

Hello!

The objective is to test if the courses emphasize memorizing facts, ideas or methods following the same distribution as before.

The variable of interest is

X: Opinion of students in how much of their coursework emphasized memorizing facts, ideas, or methods. Categorized: 1_"Very little", 2_" Some", 3_" Quite a bit" and 4_"Very much"

It is known for a survey made in 2014 that the percentages for each category are: 1_Very little: 21.5%, 2_Some: 33.7%, 3_Quite a bit: 27.7% and 4_Very much: 17.1%

To test if the current situation follows the same distribution as the historical data (from 2014) you have to conduct a Goodness to Fit Chi-Square test.

The hypotheses are:

H₀: P₁= 0.215; P₂= 0.337, P₃= 0.277 and P₄= 0.171

H₁:

α: 0.01

X^2= sum[\frac{(O:i-E_i)^2}{E_i} ]~~X^2_{k-1}

k= number of categories of the variable.

This test is always one-tailed (right), which means that you will reject the null hypothesis to high values of X² (when the observed and expected frequencies for each category are too different)

The critical value is:

X^2_{k-1;1-\alpha }= X^2_{3;0.99}= 11.345

You will reject the null hypothesis if X^2_{H_0} \geq  11.345

You will not reject the null hypothesis if X^2_{H_0} < 11.345

Before calculating the statistic under the null hypothesis, you have to calculate the expected value for each category following the formula:

E_i= n*P_i

n= 400

E₁= n*P₁= 400*0.215= 86

E₂= n*P₂= 400*0.337= 134.8

E₃= n*P₃= 400*0.277= 110.8

E₄=n*P₄= 400*0.171= 68.4

The observed frequencies are:

O₁= 39

O₂= 139

O₃= 148

O₄= 74

X^2_{H_0}= (\frac{(39-86)^2}{86} )+(\frac{(139-134.8)^2}{134.8} )+(\frac{(148-110.8)^2}{110.8} )+(\frac{(74-68.4)^2}{68.4} )= 38.76

As said before, this test is one-tailed to the right (always) and so is its p-value:

P(X₃²≥38.76)= 1 - P(X²₃<38.76)= 1 - 1 ≅ 0

p-value < 0.00001

Using both approaches (p-value and critical value) the decision is to reject the null hypothesis.

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8 0
4 years ago
Solve for the mean and median of the following data: 20, 10, 15, 18, 12, 17
loris [4]
<h2><u>Mean and Median</u></h2>

<h3>solve for the mean and median of the following data: 20, 10, 15, 18, 12, 17</h3>

<h3><u>Mean</u></h3>

To find the mean of a data set, use the formula:

<u>mean</u> = <u>sum of the data points</u>/<u>number of the data points</u>

We will determine the sum of the data points.

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Since the number of data points is 6, we will divide the sum and the number of data points as shown in the formula above.

  • 92/6
  • 15.3

<u>Answer:</u>

  • The mean of the data set is <u>15.3</u>.

<h3><u>Median</u></h3>

To find the median of the data set, arrange the data set into ascending order and the value in the middle is the median. The median should be an even number.

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  • 10, 12, 15, 17, 18, 20

The middle value is 15 and 17. Find out their sum and divide it into 2.

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<u>Answer:</u>

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At the farm, Justin picks 3 bushels of fruits. The bushels weigh 8 1/4 pounds, 6 1/2 pounds, and 6 5/8 pounds. What is the avera
blondinia [14]
ANSWER

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EXPLANATION

To find the average weight per bushel, we add all the three weight and divide by 3.


Average \: Weight =  \frac{8 \frac{1}{4}  + 6 \frac{1}{2} + 6 \frac{5}{8}  }{3}


We convert all the mixed numbers to improper fraction to obtain,


Average \: Weight =  \frac{ \frac{33}{4}  +  \frac{13}{2} + \frac{53}{8}  }{3}


The least common denominator for the fractions in the numerator is 8.


This implies that,

Average \: Weight =  \frac{ \frac{66 + 52 + 53}{8} }{3}

This simplifies to


Average \: Weight =  \frac{ \frac{171}{8} }{3}


This gives us,

Average \: Weight =   \frac{171}{24}



Average \: Weight =   \frac{57}{8}


Average \: Weight =  7 \frac{1}{8}

7 0
4 years ago
If m = 6 , and ( x , y ) = ( − 1 , − 3 ) , solve y = m x + b for b .
Leya [2.2K]
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B is 3
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