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givi [52]
3 years ago
5

Brett currently spends $160 each month on gas.

Mathematics
1 answer:
masha68 [24]3 years ago
3 0

Answer:

Spend on gas each month with the new car=$120.

Step-by-step explanation:

Hope it helps :)

Have a good day/night

Brainliest pls?

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: Find the approximate perimeter of the isosceles triangle A OPD.
AleksAgata [21]

Answer:

24.98 units

Step-by-step explanation:

The picture of the question in the attached figure

we have the coordinates

P(1,-6),D(4,3),O(7,-6)

The perimeter of triangle OPD is equal to

P=OP+PD+OD

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

step 1

Find the distance OP

we have

O(7,-6),P(1,-6)

substitute in the formula

d=\sqrt{(-6+6)^{2}+(1-7)^{2}}

d=\sqrt{(0)^{2}+(-6)^{2}}

d_O_P=6\ units

step 2

Find the distance PD

we have

P(1,-6),D(4,3)

substitute in the formula

d=\sqrt{(3+6)^{2}+(4-1)^{2}}

d=\sqrt{(9)^{2}+(3)^{2}}

d_P_D=\sqrt{90}\ units

step 3

Find the distance OD

we have

O(7,-6),D(4,3)

substitute in the formula

d=\sqrt{(3+6)^{2}+(4-7)^{2}}

d=\sqrt{(9)^{2}+(-3)^{2}}

d_O_D=\sqrt{90}\ units

step 4

Find the perimeter

P=6+\sqrt{90}+\sqrt{90}

P=6+9.49+9.49=24.98\ units

4 0
3 years ago
Choose all answers that apply.
Aleksandr [31]

Answer:

It should be C

Step-by-step explanation:

You want to cancel out the x variables

3 0
3 years ago
PLEASE HELP WILL MARK BRAINLEIST
wolverine [178]

Answer:

The second one.

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Evaluate the integral:
Bogdan [553]

Substitute x = √7 sin(t) and dx = √7 cos(t) dt. Then

∫ √(7 - x²) dx = ∫ √(7 - (√7 sin(t))²) • √7 cos(t) dt

… = √7 ∫ √(7 - 7 sin²(t)) cos(t) dt

… = 7 ∫ √(1 - sin²(t)) cos(t) dt

… = 7 ∫ √(cos²(t)) cos(t) dt

We require that -π/2 ≤ t ≤ π/2 in order for the substitution we made to be reversible. Over this domain, cos(t) ≥ 0, so

√(cos²(t)) = |cos(t)| = cos(t)

and the integral reduces to

… = 7 ∫ cos²(t) dt

Recall the half-angle identity for cosine:

cos²(t) = (1 + cos(2t))/2

Then the integral is

… = 7/2 ∫ (1 + cos(2t)) dt

… = 7/2 (t + 1/2 sin(2t)) + C

… = 7t/2 + 7/4 sin(2t) + C

Get the antiderivative back in terms of x. Recall the double angle identity for sine:

sin(2t) = 2 sin(t) cos(t)

We have t = arcsin(x/√7), which gives

sin(t) = sin(arcsin(x/√7)) = x/√7

cos(t) = cos(arcsin(x/√7)) = √(7 - x²)/√7

Then

∫ √(7 - x²) dx = 7/2 arcsin(x/√7) + 7/4 • 2 sin(arcsin(x/√7)) cos(arcsin(x/√7)) + C

… = 7/2 arcsin(x/√7) + x/2 √(7 - x²) + C

5 0
2 years ago
Add. Express your answer as a fraction. Do not include spaces in your answer.<br> 5/1/4+15.5
MAVERICK [17]

Answer:

The answer is 20/3/4(without spaces) or 20 3/4.

Step-by-step explanation:

7 0
3 years ago
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