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FromTheMoon [43]
3 years ago
15

A train has one engine and six train cars. Find the total number of ways an engineer can arrange the train. (The engine must be

first.)
Mathematics
1 answer:
enot [183]3 years ago
4 0

Answer: 720 ways

Step-by-step explanation:

Given

A train has 1 main engine and remaining 6 train cars

If the engine is always in the front the remaining train cars can be arranged is

\Rightarrow \text{No. of ways}=6!=720\ \text{ways}

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Solving the expression \frac{4-5i}{2+3i} we get -\frac{7}{13}-\frac{22i}{13}

So, Option A is correct.

Step-by-step explanation:

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Multiplying and dividing by 2-3i

=\frac{4-5i}{2+3i}*\frac{2-3i}{2-3i}\\=\frac{4-5i*2-3i}{2+3i*2-3i}\\=\frac{4(2-3i)-5i(2-3i)}{(2)^2-(3i)^2}\\=\frac{8-12i-10i+15i^2)}{4-9i^2}\\We\,\,know\,\, i^2=-1\\=\frac{8-12i-10i+15(-1)}{4-9(-1)}\\=\frac{8-15-12i-10i}{4+9}\\=\frac{-7-22i}{13}\\=-\frac{7}{13}-\frac{22i}{13}

So, solving the expression \frac{4-5i}{2+3i} we get -\frac{7}{13}-\frac{22i}{13}

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Keywords: Complex numbers

Learn more about Complex numbers at:

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[math]

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[/math]

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