A train has one engine and six train cars. Find the total number of ways an engineer can arrange the train. (The engine must be
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Answer:
Step-by-step explanation:
Isolate the variable of y from one side of the equation.
-14=5(3y-10)-5y
<u>First, switch sides.</u>
Use the distributive property.
<u>DISTRIBUTIVE PROPERTY:</u>
A(B-C)=AB-AC
5(3y-10)
Multiply by expand.
5*3y=15y
5*10=50
15y-50-5y
15y-5=10y
= 10y-50
10y-50=-15
Add by 50 from both sides.
10y-50+50=-15+50
Solve.
10y=35
Then, you divide by 10 from both sides.
10y/10=35/10
Solve.
Divide the numbers from left to right.
35/10=7/2
y=7/2
Divide is another option.
7/2=3.5
- <u>Therefore, the correct answer is y=7/2.</u>
I hope this helps. Let me know if you have any questions.