Answer:
- The temperature is 8 degrees below 0
- A student's class average decreases by 8 points.
Answer:
t = 1 3/7 hours
Step-by-step explanation:
For plane 1
distance = rate *t
d1 = 40 *t
For plane 2
distance = rate * time
d2 = 100 * t
We know that d1+d2 = 200 (the planes will meet)
We know that the times will be the same because the leave at the same time.
Substitute in d1 =40t and d2 = 100t into d1+d2 = 200
d1+d2 = 200
40t + 100t = 200
Combine like terms
140t = 200
Divide each side by 140
140t/140 = 200/140
t= 200/140
t= 20/14
t = 10/7
t = 1 3/7 hours
Answer: x=14.4
Step-by-step explanation:2.5x=48-12
2.5x=36
x=14.4
Let the required point be (a,b)
The distance of (a,b) from (7,-2) is
=
But this distance needs to be betweem 50 & 60
So
Squaring all sides
2500 < (a-7)² + (b+2)² < 3600
Let a = 7
So we have
2500 < (b+2)² <3600
b+2 < 60 or b+2 > -60 => b <58 or b > -62
Also
b+2 >50 or b + 2 < -50 => b >48 or B < -52
Let us take one value of b < 58 say b = 50
So now we have the point as (7, 50)
The other point is (7,-2)
Distance between them
=
This is between 50 & 60
Hence one point which has a distance between 50 & 60 from the point (7,-2) is (7, 50)
Answer:
3x4-2x3-2x2+4x-10
Step-by-step explanation:
you just add the ones that are similar to each other.