All categories

3 years ago

I need Help please anyone

Mathematics

1 answer:

mezya [45]3 years ago

5 0

0,5 but ye don’t quote me on this one but I have a strong feeling that what it is

You might be interested in

it is 3 kilometers from Linda's house to the nearest mailbox. How far is it in meters? Be sure to include the correct unit in yo

tester [92]

Answer:

1km=1000m... thats basically the answer so the nearest mail box is 3000M

3 0

2 years ago

At the fair concession stand, a drink costs $1.50, and a hot dog costs $2.75. If Jacob has $18 to spend on food, how many of eac

Cerrena [4.2K]

Answer:

Answer is D (2 drinks and 5 hotdog's)

Step-by-step explanation: 1st answer is over as it is $19.25 for only the hotdogs. 2nd is $18.50 which is a little over. 3rd one is $22.25. And the forth one is $16.75 which is perfect because he cant buy anything else with the remainder of his money.

6 0

3 years ago

Select the correct answer. Given the formula below, solve for x. y - y1 = m(x - x1)

mario62 [17]

C would be the right answer just done the test

7 0

3 years ago

The perimeter of the hallway is 10 4/10 meters. What is the width, in meters, of the hallway?

Romashka [77]

So you have two of those--when you add those together, you get "seven and eight-tenths," or 7.8 The 2 shorter sides are what's left to still measure. If the total perimeter is 10.4, you get the shorter sides by: 10.4 - 7.8 = 2.6, but REMEMBER, the 2.6 is BOTH shorter sides added together, so each ONE of them is 1.3 SO... your hallway/rectangle is 3.9 meters on each long side, and 1.3 meters on each short side. i hope this helps you

4 0

3 years ago

Help please solve <img src="https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7B6x%5E5%2B11x%5E4-11x-6%7D%7B%282x%5E2-3x%2B1

Shkiper50 [21]

Answer:

$\displaystyle -\frac{1}{2} \leq x < 1$

Step-by-step explanation:

Inequalities

They relate one or more variables with comparison operators other than the equality.

We must find the set of values for x that make the expression stand

$\displaystyle \frac{6x^5+11x^4-11x-6}{(2x^2-3x+1)^2} \leq 0$

The roots of numerator can be found by trial and error. The only real roots are x=1 and x=-1/2.

The roots of the denominator are easy to find since it's a second-degree polynomial: x=1, x=1/2. Hence, the given expression can be factored as

$\displaystyle \frac{(x-1)(x+\frac{1}{2})(6x^3+14x^2+10x+12)}{(x-1)^2(x-\frac{1}{2})^2} \leq 0$

Simplifying by x-1 and taking x=1 out of the possible solutions:

$\displaystyle \frac{(x+\frac{1}{2})(6x^3+14x^2+10x+12)}{(x-1)(x-\frac{1}{2})^2} \leq 0$

We need to find the values of x that make the expression less or equal to 0, i.e. negative or zero. The expressions

$(6x^3+14x^2+10x+12)$

is always positive and doesn't affect the result. It can be neglected. The expression

$(x-\frac{1}{2})^2$

can be 0 or positive. We exclude the value x=1/2 from the solution and neglect the expression as being always positive. This leads to analyze the remaining expression

$\displaystyle \frac{(x+\frac{1}{2})}{(x-1)} \leq 0$