Answer:
Domain = {x : x ≠ 4 , -4} or (-∞ , -4) ∪ (-4 , 4) ∪ (4 , ∞)
Step-by-step explanation:
<u>TO FIND :-</u>
- Domain of
<u>SOLUTION :-</u>
Domain of a function is a value for which the function is valid.
The function is valid until the denominator is 0.
So make sure that the denominator must not be 0.
Find the values of x for which the denominator becomes 0. To find it , you'll have to solve the above inequality.
We can say that <u>4 & -4 can't be domains</u> because these values will make the function undefined.
Now try putting values of x such that -4 < x < 4. You'll observe that the function will be valid for all those values of x between -4 & 4.
<u>CONCLUSION :-</u>
The function will be valid for any value of 'x' except 4 & -4. So in :-
Interval notation , it can be written as → (-∞ , -4) ∪ (-4 , 4) ∪ (4 , ∞)
Set builder notation , it can be written as → {x : x ≠ 4 , -4}
Answer:
28
Step-by-step explanation:
65% of x = 52
x= 52*100/65 = 80
now
35% of 80 = 35/100 * 80 = 28
Answer:
The answer is 15
Step-by-step explanation:
15 - 3 = 12
Answer:
x = 1/15
Step-by-step explanation:
-5(3x-1+3x) = 3
add like terms:
-5(6x-1) =3
distribute -5 throughout the Parentheses:
-30x+5= 3
move the constant to the right side and change it's sign:
-30x=3-5
calculate:
-30x= -2
Divide both sides by -30:
x = 1/15
Answer:
If I calculated correctly, the tangent line is horizontal where x ≈ -5.3 + 9.3i, and -5.3 - 9.3i
I'm somewhat concerned at having gotten complex numbers, and strongly recommend going through the steps to see if I missed anything. I checked it myself and don't see any errors.
Step-by-step explanation:
You can do this by taking the derivative of the function and solving for zero:
f(x) = 2x³ + 32x² + 220x + 11
f'(x) = 6x² + 64x + 220
f'(x) = 2(3x² + 32x + 110)
We can't factor that further, so let's do it the long way, starting by letting f'(x) equal zero:
0 = 2(3x² + 32x + 110)
0 = 3x² + 32x + 110
0 = 9x² + 96x + 990
0 = 9x² + 96x + 256 + 734
0 = (3x + 16)² + 734
(3x + 16)² = -734
3x + 16 = ± i√734
3x = -16 ± i√734
x = (-16 ± i√734) / 3
x ≈ (-16 + 27.9i) / 3, and (16 - 27.9i) / 3
x ≈ -5.3 + 9.3i, and -5.3 - 9.3i
I'm always wary when I end up with complex numbers. I'd suggest double checking everything here, but I'm fairly certain I did everything correctly.
