In the scientific value of
5.893 x 10n. The standard value is 0.00005893 what is n?
To better illustrate this
phenomenon, we can explain it further under the rules of scientific notation.
For example.
<span><span>
1. </span><span> 3 x 10^3 = 3 x
100 = 300</span></span>
<span><span>2. </span><span> 3 x 10^-3 = 3 x
0.001 = 0.003</span></span>
Solution:
0.00005893 = 5.893 x 0.00001 =
5.893 x 10^-5
n= ^-5
Step-by-step explanation:
The solution to this problem is very much similar to your previous ones, already answered by Sqdancefan.
Given:
mean, mu = 3550 lbs (hope I read the first five correctly, and it's not a six)
standard deviation, sigma = 870 lbs
weights are normally distributed, and assume large samples.
Probability to be estimated between W1=2800 and W2=4500 lbs.
Solution:
We calculate Z-scores for each of the limits in order to estimate probabilities from tables.
For W1 (lower limit),
Z1=(W1-mu)/sigma = (2800 - 3550)/870 = -.862069
From tables, P(Z<Z1) = 0.194325
For W2 (upper limit):
Z2=(W2-mu)/sigma = (4500-3550)/879 = 1.091954
From tables, P(Z<Z2) = 0.862573
Therefore probability that weight is between W1 and W2 is
P( W1 < W < W2 )
= P(Z1 < Z < Z2)
= P(Z<Z2) - P(Z<Z1)
= 0.862573 - 0.194325
= 0.668248
= 0.67 (to the hundredth)
Answer:
In the comments
Step-by-step explanation:
Answer:
(3,3)
Step-by-step explanation:
Using the midpoint formula:
Hope this helps!
Z=-3 is the correct answer. Use math papa if you need help with the steps on how we got z=-3
