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Lerok [7]
2 years ago
9

I need help on how to solve these problems (please do not give me the answers i just want to learn how to solve these types of p

roblems :))
Part A: Find a rational number that is between 7.7 and 7.9. Explain why it is rational.

Part B: Find an irrational number that is between 7.7 and 7.9. Explain why it is irrational. Include the decimal approximation of the irrational number to the nearest hundredth.
Mathematics
1 answer:
adelina 88 [10]2 years ago
8 0

For part A, all you need to do is find an number between 7.7 and 7.9 but the number must terminate, or end.

For part B you must find a number that does not end and does not repeat, but round that number to the nearest hundredth.

You might be interested in
Order the ratios from least to greatest:
ss7ja [257]

Answer:

13:6 ; 9:4 ; 5:2 ; 20:7 ; 10:3

Step-by-step explanation:

8 0
2 years ago
A box contains 24 transistors,4 of which are defective. If 4 are sold at random,find the following probabilities. i. Exactly 2 a
zavuch27 [327]

SOLUTION

This is a binomial probability. For i, we will apply the Binomial probability formula

i. Exactly 2 are defective

Using the formula, we have

\begin{gathered} P_x=^nC_x\left(p^x\right?\left(q^{n-x}\right) \\ Where\text{ } \\ P_x=binomial\text{ probability} \\ x=number\text{ of times for a specific outcome with n trials =2} \\ p=\text{ probability of success = }\frac{4}{24}=\frac{1}{6} \\ q=probability\text{ of failure =1-}\frac{1}{6}=\frac{5}{6} \\ ^nC_x=\text{ number of combinations = }^4C_2 \\ n=\text{ number of trials = 4} \end{gathered}

Note that I made the probability of being defective as the probability of success = p

and probability of none defective as probability of failure = q

Exactly 2 are defective becomes the binomial probability

\begin{gathered} P_x=^4C_2\times\lparen\frac{1}{6})^2\times\lparen\frac{5}{6})^{4-2} \\ P_x=6\times\frac{1}{36}\times\frac{25}{36} \\ P_x=\frac{25}{216} \\ =0.1157 \end{gathered}

Hence the answer is 0.1157

(ii) None is defective becomes

\begin{gathered} \lparen\frac{5}{6})^4=\frac{625}{1296} \\ =0.4823 \end{gathered}

hence the answer is 0.4823

(iii) All are defective

\begin{gathered} \lparen\frac{1}{6})^4=\frac{1}{1296} \\ =0.00077 \end{gathered}

(iv) At least one is defective

This is 1 - probability that none is defective

\begin{gathered} 1-\lparen\frac{5}{6})^4 \\ =1-\frac{625}{1296} \\ =\frac{671}{1296} \\ =0.5177 \end{gathered}

Hence the answer is 0.5177

3 0
10 months ago
There are 20 boys in Fred's scout troop, and 12 of them are going on the 50-mile hike. What percent of the boys are going on the
anygoal [31]

Answer:

60%

Step-by-step explanation:

12/20=0.6

0.6=60%

4 0
3 years ago
Read 2 more answers
PLEASE HELP QUICKLY 15 POINTS, WILL MARK BRAINLIEST
zhuklara [117]

Answer:

Binomial expansion also known as binomial theorem is a quick and easy way of expanding by multiplying binomial expression that has been raised to large power.

Step-by-step explanation:

A binomial is a polynomial with two terms. From the above definition given, if for instance an expression of (5x-4)²² was given, it wouldn't be that easy to multiply out by hand which is why the binomial theorem formula was created.

Another example to buttress this point is if we have (a³+2ab+b2)(a+b) expanding this will give a³+3a2b+b³ = a³+3a2b) +3ab²+b³)a+b = a⁴+ 4a³b+ 6a²b²+4ab³+b4..

This calculation could go on and on because it gets longer as we go but to make it easier and simpler, the best method to use here is the binomial theorem or expansion and the formula states thus:

n. n

(x+y)ⁿ = € {n}xⁿ-k*y^k

k=0 {k} = € {n} x^k*y^n-k

k=0 {k}

{n}

{k}. = binomial coefficient of each term

It should from the example given that we have index power(power raised)called exponent such that when an exponent is 0, we get 1 , i.e anything raised to power 0 =1

e.g (x+y)^0 = 1

And also when an exponent is 1, then the answer remain unchanged such that (x+y)¹= x+y. An exponent of 2 means to multiply given term by itself in two times and so on.

So to expantiate an expression like

a³+3a²b+3ab²+b³.. This expression has its index power(exponent) start with 3 such that .

The a goes down in the form.. 3,2,1,0 while the exponents of b go upwards in the form 0,1,2,3coeffiThe terms 0-n goes thus

k=0 k=1 k=2 k=3

a³ a² a 1

1 b. b² b³

which equals an-kbk.. This is confusing right. This is how it works

k=0 k=1 k=2 k= 3

an-kb^k. an-kb^k an-kb^k an-k^bk

a³-0b^0. a3-1b¹ a3-2b2 a3-3b3

a³ a²b. ab² b³

So when we put all this together we have: a³+a²b+ ab²+ b³. Actually this answer is correct but what we are missing here is the coefficient of n because we needs to include it.

So this becomes a³+3a²b +3ab²+b³ , the coefficient of n here is 3.

Now if we are to look at the result we got before from(a+b)^0 up to (a+b)³

And here that we have 3 as coefficient but where it is not shown we put 1 which is.

1

1a+ 1b

1a+2ab+ 1b²

1a³ +3a²b+3ab²+1b³... We solve this using pascal triangle.

1 This is solved by adding

1 1 each two numbers above

1 2 1 together to get the one

1 3 3 1 below.

1 4 6 4 1

This pascal pattern can be used for any exponents..1,2,3,5....60...120....n

Binomial theorem is basically the essence of this Pascal triangle pattern.

As stated earlier that the formula of binomial theorem is

n

€{n}a^n-kb^k

n-1 where €= summation

n= numbers given

k=coefficient of n

Now, let's to put into practical by solving this expression.

(x+y)ⁿ=€ⁿ {n}a^n-k* b^k

k=0 {k}

But before we solve this, its important we know the basis of Pascal triangle by using factorial to solve it with the formula n!/k!(n-k)! Such that

Factorial is n multiplied in descending order(i.e multiplying Numbers between 1-n)

K- coefficient of n

N- product of all the numbers between 1&n. For instance we are given this 4!/3!(4-3)! = 4!/3!*1!

= 4*3*2*1/3*2*1 *1 = 24/6 = 4

Now let's go back to the previous example of (x+y)ⁿ where n=4

(x+y)⁴= €⁴ {4} x^4-k*y^k

k=0 {k}

(x+y)⁴= €{4} (x^4-0)y^0 + {4} (x^4-1) *y¹

{0} {1}

+{4} (x^4-2)*y² + {4} (x^4-3)*y³

{2} {3}

+ {4} (x^4-4) * (y⁴)

{4}

= 1*x⁴y^0 + 4*x³y¹ + 6*x²y² +4*x¹y³ +1*x^0y⁴=

x⁴+4x³y +6x²y² + 4xy³ +y⁴(Final answer)

Please note that:

When solving binomial theorem expression, the easiest way to do this is by remembering the patterns below:

* first term's exponent start at n and go down

* second term's exponent start at 0 and goes up

* coefficient are solved with pascal triangle using n!/k!(n-k)!

5 0
3 years ago
You opened your first savings account 3 months ago. So far, you have earned $9.90 in simple interest, at an annual interest rate
LekaFEV [45]
I=prt
9.90=p (.06)(3)
9.90=p(.18)
9.90/.18=p.18/.18
55=p

I put in $55 into the account when I opened it.
6 0
3 years ago
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