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3 years ago

Add (5x^4+ 2x^3– 1)+(3x² – 3x + 3)

Mathematics

2 answers:

jolli1 [7]3 years ago

8 0

Answer:

5x^4+ 2x^3+3x² – 3x + 2

Step-by-step explanation:

(5x^4+ 2x^3– 1)+(3x² – 3x + 3)

Combine like terms

5x^4+ 2x^3+3x² – 3x + 3– 1

The only like terms are the constants

5x^4+ 2x^3+3x² – 3x + 2

olga2289 [7]3 years ago

7 0

Answer:

5x^4 + 2x^3 -3x^2 - 3x + 2

Step-by-step explanation:

Expanding out the brackets:

5x^4 + 2x^3 - 1 + 3x^2 - 3x + 3.

Simplifying gives

5x^4 + 2x^3 - 3x^2 - 3x + 2

Remember you can only add x's together if they have the same power. This makes sense why you can 2 to -1 because they are both the same power of x, x^0. (which equals 1 by default)

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a cell phone company found that 15 of their phones sold in June were defective. The company sold 250 phone in June. How many of

larisa [96]

Write and solve an equation of ratios, as follows:

15 250

----- = ------- = 10/12.

x 300

Then 15(12) = 10x, and x = 18. The company could well predict that 18 out of the 300 phones it sells in July will be defective, based upon past history.

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3 years ago

Solve the simultaneous equations:<br> 3x + 2y = 35 <br> 2x + 3y = 30

lesya [120]

Answer:

nuber 1

Simplifying

3x + 2y = 35

Solving

3x + 2y = 35

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-2y' to each side of the equation.

3x + 2y + -2y = 35 + -2y

Combine like terms: 2y + -2y = 0

3x + 0 = 35 + -2y

3x = 35 + -2y

Divide each side by '3'.

x = 11.66666667 + -0.6666666667y

Simplifying

x = 11.66666667 + -0.6666666667y

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2 years ago

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likoan [24]

Answer:

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Step-by-step explanation:

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2 years ago

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Determine what comes next in the given pattern.<br><br>15, 10, 14, 10, 13, 10,

mojhsa [17]

Answer:

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3 years ago

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NutritionCalc Plus uses the equations from the National Academy of Medicine to calculate the Estimated Energy Requirement (EER)

olga nikolaevna [1]

Answer:

The correct option is (A).

Step-by-step explanation:

The equation for the Estimated Energy Requirement (EER) of 19 or more years older men is:

$EER = 662 - (9.53 \times AGE) + PA \times (15.91 \times WT + 539 \times HT)$

Here,

AGE = age counted in years

PA = appropriate physical activity factor

WT = weight in kilograms

HT = height in meters

The physical activity factor for men and women is:

Activity Level PA (men) PA (Women)

Sedentary 1.00 1.00

Low 1.11 1.12

Active 1.25 1.27

Very Active 1.48 1.45

Given:

AGE = 22 year-old male college student

PA = low = 1.11

WT = 180 pounds = 81.6466 kg

HT = 5'10" = 1.778 m

Compute the value of EER as follows:

$EER = 662 - (9.53 \times AGE) + PA \times (15.91 \times WT + 539 \times HT)$

$= 662 - (9.53 \times 22) + 1.11 \times (15.91 \times 81.6466 + 539 \times 1.778)\\\\=662-209.66+1.11\times (1298.997406+958.342)\\\\=452.34+2505.64674066\\\\=2957.98674066\\\\\approx 2962$

Thus, the EER for a 22-year-old male college student is approximately 2962 kcal.

The correct option is (A).

6 0

2 years ago