Using the problem, create an equation to find the number (x).
Three less than (so x minus 3) 6 times a number (6 times x) equals 39.
6x-3=39, solve for x.
x = 7
3 divided by x to find the what the amount of x is
<h2>Hello!</h2>
The answer is:
C. Cosine is negative in Quadrant III
<h2>
Why?</h2>
Let's discard each given option in order to find the correct:
A. Tangent is negative in Quadrant I: It's false, all functions are positive in Quadrant I (0° to 90°).
B. Sine is negative in Quadrant II: It's false, sine is negative in positive in Quadrant II. Sine function is always positive coming from 90° to 180°.
C. Cosine is negative in Quadrant III. It's true, cosine and sine functions are negative in Quadrant III (180° to 270°), meaning that only tangent and cotangent functions will be positive in Quadrant III.
D. Sine is positive in Quadrant IV: It's false, sine is negative in Quadrant IV. Only cosine and secant functions are positive in Quadrant IV (270° to 360°)
Have a nice day!
The best answer would be
2.4 x 10 ^6
10 to the sixth power multiplied by 2.4
<u>Shape #1: A square.</u>
Every side is 4 units long.
The perimeter is 16 units.
The area is <em>16 </em>square units.
<u>Shape #2: A rectangle.</u>
The length is 7.9 units.
The width is 0.1 unit.
The perimeter is 16 units.
The area is <em>0.79</em> of a square unit.
<u>Shape #3: A circle.</u>
The diameter is (16/π) units. (about 5.093 units)
The perimeter (circumference) is 16 units.
The area is (64/π) square units. (about <em>20.37</em> square units)
