Question

The owner of a grocery store wants to mix two kinds of candy together to make 15 lb that he can sell for $5.00 per lb. He wants to use chocolate candies that he sells for $7.00 per lb and sugar candies that he sells for $2.00 per lb. How many pounds of each should the owner use?
_ pounds of chocolate candies
_ pounds of sugar candies
=OWO=

Answer 1

Answer:

9lb chocolate candies

6lb sugar candies

Step-by-step explanation:

Yes, I also happen to go to RSM. (6b)

Equation: 7x+2(15-x)=5*15

Solve:

7x+(2)(15)+(2)(−x)=(5)(15)

7x+30+(−2x)=75

(7x+(−2x))+(30)=75

5x+30=75

5x=45

x=9lb chocolate candies

Now, calculate the sugar candies.

15-9=6lb sugar candies

Answer 2

Answer: 9 pounds of chocolate and 6 pounds of sugar candies

Let's define the variables:

C = pounds of chocolate candies used.

S = pounds of sugar candies used.

We know that he wants to make a total of 15lb, then:

C + S = 15

We also want that the price per pound to be equal to 5$.

This means that the price of the 15 pounds will be the same as the price of the un-mixed candies.

C*$7.00 + $2.00*S = $5.00*15

Then we have a system of equations:

C + S = 15

C*$7.00 + $2.00*S = $5.00*15

To solve this system, we need to start by isolating one of the variables, i will isolate C in the first equation:

C = 15 - S

now we can replace that in the other equation:

(15 - S)*$7.00 + $2.00*S = $5.00*15

Now we can solve this for S.

$105 - $5.00*S = $75

$105 - $75 = $5.00*S

$30 = $5.00*S

$30/$5 = S = 6

Then there are 6 pounds of sugar candy, and we can use the equation:

C + S = 15

C + 6 = 15

C = 15 - 6 = 9

There are 9 pounds of chocolate candy in the mix.

Step-by-step explanation: