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4 years ago

13

Is linear algebra the same as intermediate algebra?

2 answers:

alekssr [168]4 years ago

5 0

Answer:

No

Step-by-step explanation:

cluponka [151]4 years ago

4 0

Linear algebra is a branch of algebra that deals with the study of linear functions and their various representations. It is very similar to physics as deeply covers matrices and vectors.

Intermediate algebra is Algebra II. Some places even call it Algebra II. Algebra II briefly overviews various types of functions, like quadratic, linear, exponential, logarithmic, sine and cosine, tan, etc.

Linear algebra is specifically designed to cover linear functions.

Intermediate algebra or algebra II overviews all the types of functions.

Both are easy and fun. I suggest you take both. lol

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Anit [1.1K]

The perimeter is 4 $\frac{16}{13}$ or 5 $\frac{3}{13}$

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3 years ago

The employees of a firm that manufactures insulation are being tested for indications of asbestos in their lungs. The firm is re

crimeas [40]

Answer:

attached below

Step-by-step explanation:

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3 years ago

How would you solve (-1,4),y=3x+5

astraxan [27]

Answer:

y = 12x

Step-by-step explanation:

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5 0

4 years ago

The number name of 70080067 <br>In Indian System

zloy xaker [14]

Answer:

Seven crore eighty thousands sixty-seven.

Step-by-step explanation:

70080067

Seven crore eighty thousands sixty-seven.

3 0

3 years ago

Jim and Dianna want to save for their child’s college expenses. They find an annuity that pays 6% annual interest, compounded mo

lana66690 [7]

Answer:

future value = $49163.8

so required amount will be $491200 nearest $100

Step-by-step explanation:

given data

annual interest rate = 6 %

annuity = $300 per month

time period = 10 years

to find out

how much money will they have for the college expenses

solution

we know that effective rate will be

effective rate = $\frac{0.06}{12}$

effective rate = 5 × $10^{-3}$

number of payment = 12 × 10 = 120

so future value will be express as

future value = annuity × $\frac{(1+r)^t-1}{r}$ .........1

future value = 300 × $\frac{(1+5*10^{-3})^{120}-1}{5*10^{-3}}$

future value = 300 × 163.8793

future value = $49163.8

so required amount will be $491200 nearest $100

7 0

4 years ago