Least to greatest: 0.7 0.9 0.73 0.81
Three cards are selected from a standard deck of <span>52 </span><span>cards. Disregarding the order in which they are drawn, the possible outcomes are </span><span><span>(<span>52/3</span>)</span></span><span>. Out of these, how many include all cards of the same color (say red)? There are </span><span><span>(<span>13/3</span>)</span></span><span> ways in which you can get all 13 red cards.</span>
Joy makes 6.5 litres soup correct to the nearest 0.5 litres. She serves the soup in 280ml portions correct to the nearest 10ml. 22 people order this soup. Does joy definitely has enough soup to serve the 22 people.
Answer:
Yes, Joy definitely does has enough soup
Step-by-step explanation:
From the question, we know,
Joy make 6.5 litres of soup
Serves it in 280ml portions
Step 1
We convert the portions to liters
1 ml = 0.001 litre
280 ml
= 280ml × 0.001 litre/1 ml
= 0.28litre
Step 2
We divide 6.5 liters by 0.28 to find out how many people can be served
= 6.5 ÷ 0.28
= 23.2142857143 people
We can see that 6.5 liters soup can serve 23 people approximately.
Therefore, Yes, Joy definitely does has enough soup to serve 22 people
Answer:
(A) 180
Step-by-step explanation:
We have to treat those player selections as independent events, since one doesn't influence the other (the fact you chose Joe as a guard, shouldn't have an influence on who'll pick as center, unless there's bad blood between some players... but that's a whole other story).
So, how many ways to pick 2 guards from a selection of 4? The order doesn't seem to matter here, since they don't specify for example that Joe can only play on the left side). So, it's a pure combination calculation:
C(4,2) = 6.
How many ways to pick the 2 forwards from a group of 5? Using the same calculation, we get:
C(5,2) = 10.
And of course, the coach has 3 ways to pick a center player from 3.
Then we multiply the possible ways to pick guards, forwards and center...
6 * 10 * 3 = 180 ways.
Answer:
add here be back charger
Step-by-step explanation:
