The question above has multiple choices as below;
<span>a. </span>Wear aggregation.
<span>b.
</span>Wear mitigation.
<span>c. </span>Wear prevention
<span>d.
</span>Wear leveling
The answer is d) Wear leveling.
This technique by some SSD controllers to increase the
memory’s lifetime is called wear leveling. The mechanism for this principle is
simple: distribute the entries for all the blocks evenly so that they will wear
out evenly. Flash controller typically manages wear leveling and uses a wear
leveling algorithm to control which physical block to use.
Is there answer choices because I’m not understanding what you want me to answer
Answer:
Option B is not correct
Explanation:
Dialogues become problematic when they appear automatically because of high level incompatibility
Answer:
Following are the program to this question:
#include <iostream>//defining header file
using namespace std;
void squareOfAsterisks(int x) //defining method squareOfAsterisks
{
int i,j; //defining integer variable
for(i=1;i<=x;i++) //defining loop to print column value
{
for(j=1;j<=x;j++) //defining loop to print row value
{
cout<<"*"; //print value
}
cout<<endl; //for line break
}
}
int main() //defining main method
{
int x; //defining integer variable
cout<<"Enter any number: "; //print message
cin>>x; //input value from user
squareOfAsterisks(x); //calling the method and pass the value
return 0;
}
Output:
Enter any number: 4
****
****
****
****
Explanation:
The description of the above program can be given as follows:
- In the given program a method "squareOfAsterisks" is declared, that accepts an integer value "x" in its arguments, inside the method two integer variable I, j is used, that uses a to print the given pattern.
- In the main method, an integer variable x is declared, which takes input from the user end, and then calls the method, that is "squareOfAsterisks" and passes its value.
