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3 years ago

PLEASE HELP ILL GIVE BRAINLIEST

Mathematics

1 answer:

Stolb23 [73]3 years ago

7 0

Answer:

x = 150°

Step-by-step explanation:

From the picture attached,

Segment AC and segment BC are the tangents to circle O.

By the property of angle between tangent and the radius of a circle,

"Angle between the radius and tangent drawn to the circle is 90°"

m(∠OAC) = m(∠OBC) = 90°

Sum of opposite angles of the quadrilateral OBCA is 180°,

m(∠OAC) + m(∠OBC) = 180°

Therefore, quadrilateral OBCA is a cyclic quadrilateral.

By the same property of cyclic quadrilateral,

m(∠AOB) + m(∠ACB) = 180°

x° + 30° = 180°

x = 180 - 30

x = 150°

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