Answer: sin of theta = (√55)/8
Step-by-step explanation:
Cosine is the x-value divided by the hypotenuse. We now know that since cosine is 3/8, that the hypotenuse is 8. In order to find the third side of the triangle (which would be the v-value), we must use Pythagorean theorem. The third side is square root 55. Sine equals the y-value divides by the hypotenuse. We know both of those values, so Sine of theta = square root of 55 divided by 8.
If Heather puts in 1.36% of her salary into a retirement account and she makes $63,000 in a year, this can be solved by 1.36% x 63000. First convert 1.36% into a decimal. To do this, divide by 100.
1.36/100=0.0136
1.36% x 63000
=0.0136 x 63000
=856.8
Heather would put $856.8 in for the whole year. To find how much per month, divide by 12.
856.8/12=71.<span>4
</span>Rounded to the nearest dollar is $71.
Heather would put $71 into a retirement account each month.
<em>
</em><em>Note: This was solved by multiply the percent and then dividing by 12 months. You could also do this by dividing by 12 months first and then multiplying the percent.</em>
Answer:
Wednesday (9 weeks later) = 10th October.
Step-by-step explanation:
We label the days with the initials of the names.
M= 4
D = 7
B = 6
LCM of 6 +7 = 42
LCM of 6+7 + 4 = 84
We find 84 is the amount of days we need to add on to july 18th
We first find the weeks 84/7 = 9 weeks.
As Wednesday July 18th is exclusive it would be 84 days after this event.
18+ 84 = 102 days.
31 days in july = 31
31 days in Aug = 31
30 days in Sept = 30
= 92
102-92 = 10
We now know date is Wednesday 10th October
We can check 84 days = 9 weeks
13 days in July makes 31st july
31 days in Aug makes 31st Aug
30 days in Sept makes 30th Sept
= 74 days + 10 days = 84
10th October is the checked date and we know it is also a Wednesday as Wednesday had stayed exclusive and prove that there are 7 days in the week to account x 9, to account for an exact 9 weeks later duration.
Answer:
The correct answer is 9 m per 
Step-by-step explanation:
Force is defined by mass of an object times it's acceleration.
Let the mass of the object be m kilograms.
When a force of 30 N acts on a certain object the acceleration of the object is 5 m per
∴ 30 = m × 5
⇒ m = 6.
If the force is changed to 54 N, let the acceleration of the object be x m per .
∴ 54 = m × x
⇒ x = 
= 9
Thus when the force is 54 N, the acceleration of the object is 9 m per .
3/5, 1, 13/8, 9/5 this is the answer to your question
