8 seconds
The hardest part of this is setting up the equation -- the calculations are pretty easy.
You're told that the time (needed to go from 0 to 100 MPH) is inversely proportional to the horsepower: what this means is that as horsepower gets larger, time gets smaller. This makes sense since the more horsepower you have, the less time it will take you to get to 100 MPH
You can think of this as:
200 HP = 10 seconds
250 HP = x seconds
You set the equation up as:
250 HP / 200 HP = 10 sec / x sec
Now, just cross multiply and solve:
250 / 200 = 10 / x
250x = (200 x 10)
250x = 2000
x = 2000 / 250
x = 8
So, as you increase the horsepower from 200 to 250, the time decreases from 10 seconds to 8 seconds.
Hope this helps!
Good luck.
Answer:
the answer is C
Step-by-step explanation:
You are running a fuel economy study. One of the cars you find is blue. It can travel 30 and one half miles30 1 2 miles on 1 and one fourth gallons1 1 4 gallons of gasoline. Another car is red. It can travel 25 and three fifths miles25 3 5 miles on four fifths gallon 4 5 gallon of gasoline. What is the unit rate for miles per gallon for each car? Which car could travel the greater distance on 1 gallon1 gallon of gasoline?
Blue car: 30.5 / 1.25 =24.4 miles per gallon
Red car: 25.6/0.80 =32 miles per gallon
You can easily see that the Red car travel farther on 1 gallon of gasoline.
This means that for a given year that Indiana became a state, Arizona became a state 96 years later. The expression (b) y+96=1896 is correct.
Answer:
The ray that goes parallel to the main axis after passing through the lens should also be parallel from the object to the lens
Step-by-step explanation:
To form the image of an object using a convex lens, ray diagrams are used. The following steps are followed when drawing ray diagrams.
1) Light rays are drawn from the object incidented on the lens and parallel to the principal axis. The incident light refracts (bends) through the lens and converges at the focal point at the other side of the lens.
2) Another incident light passes through the optical centre undeflected and intersect with the refracted ray at the other side of the lens.
Based on the above points, Roshan made an error by drawing the ray that goes parallel to the main axis and after passing through the lens made the same ray to be parallel from the object to the lens instead of refracting (bending) after passing through the lens.
