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Effectus [21]
3 years ago
9

Help me please don't know this

Mathematics
2 answers:
nignag [31]3 years ago
7 0

Answer:

1.multiply both sides by 5 n=−1/5x5 cancel out the 5 so n=-1

2.add both sides by 13 n=-12+13 simplify -12+13 to 1 n=1

Step-by-step explanation:

larisa86 [58]3 years ago
4 0

n/5 = -1/5

5n = -5

<u>n = -1</u>

n - 13 = -12

n = -12 + 13

<u>n = 1</u>

n + 15 = -10

n = -10 - 15

<u>n = -25</u>

-5n = 1

<u>n = -1/5</u>

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According to the Fundamental Theorem of Algebra, the graph of f(x) = x2 - 4x + 3, has roots. From the graph we can see that it h
andreyandreev [35.5K]

Answer:

The graph f(x)=x^2-4x+3  has two zeros namely 3 and 1.

Step-by-step explanation:

Consider the given equation of graph f(x)=x^2-4x+3

According to the Fundamental Theorem of Algebra

For a given polynomial of degree n can have a maximum of n roots.

Thus, for the given equation f(x)=x^2-4x+3  the degree of polynomial is 2 , thus the function can have maximum of 2 roots.

We know at roots the value of function is 0 that is f(x) = 0,

Substitute f(x) = 0 , we get, f(x)=x^2-4x+3=0

This is a quadratic equation, x^2-4x+3=0

We first solve it manually and then check by plotting graph.

Quadratic equation can be solved using middle term splitting method,

here, -4x can be written as -x-3x,

x^2-4x+3=0 \Rightarrow x^2-x-3x+3=0

\Rightarrow x(x-1)-3(x-1)=0

\Rightarrow (x-3)(x-1)=0

Using zero product property, a\cdot b=0 \Rightarrow a=0\ or \ b=0

\Rightarrow (x-3)=0 or \Rightarrow (x-1)=0

\Rightarrow x=3 or \Rightarrow x=1

Thus, the two zero of f(x) are 3 and 1.

We can also see on graph attached below that the graph f(x)=x^2-4x+3  has two zeros  namely 3 and 1.  

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