Answer:
Step-by-step Explanation:
![\huge \frac{2 + \sqrt[3]{3} }{ \sqrt[3]{6} } \\ \\ = \huge \frac{(2 + \sqrt[3]{3} )}{ \sqrt[3]{6} } \times \frac{ \sqrt[3]{6} \times \sqrt[3]{6} }{\sqrt[3]{6} \times \sqrt[3]{6}} \\ \\ = \huge \frac{(2 + \sqrt[3]{3} )}{ \sqrt[3]{6} } \times \frac{ \sqrt[3]{6 ^{2} } }{\sqrt[3]{6^{2}} } \\ \\ = \huge \frac{(2 + \sqrt[3]{3} )\sqrt[3]{6} }{ \sqrt[3]{6} \times \sqrt[3]{6 ^{2} }} \\ \\ = \huge \frac{(2 \sqrt[3]{6} + \sqrt[3]{3} \sqrt[3]{6} )}{ \sqrt[3]{6 ^{3} }} \\ \\ = \huge \orange{\frac{2 \sqrt[3]{6} + \sqrt[3]{18} }{ 6} }](https://tex.z-dn.net/?f=%20%5Chuge%20%5Cfrac%7B2%20%2B%20%20%5Csqrt%5B3%5D%7B3%7D%20%7D%7B%20%5Csqrt%5B3%5D%7B6%7D%20%7D%20%20%5C%5C%20%20%5C%5C%20%20%3D%20%20%5Chuge%20%5Cfrac%7B%282%20%2B%20%20%5Csqrt%5B3%5D%7B3%7D%20%29%7D%7B%20%5Csqrt%5B3%5D%7B6%7D%20%7D%20%20%5Ctimes%20%20%5Cfrac%7B%20%5Csqrt%5B3%5D%7B6%7D%20%20%5Ctimes%20%20%5Csqrt%5B3%5D%7B6%7D%20%7D%7B%5Csqrt%5B3%5D%7B6%7D%20%20%5Ctimes%20%20%5Csqrt%5B3%5D%7B6%7D%7D%20%20%5C%5C%20%20%5C%5C%20%3D%20%20%5Chuge%20%5Cfrac%7B%282%20%2B%20%20%5Csqrt%5B3%5D%7B3%7D%20%29%7D%7B%20%5Csqrt%5B3%5D%7B6%7D%20%7D%20%20%5Ctimes%20%20%5Cfrac%7B%20%5Csqrt%5B3%5D%7B6%20%5E%7B2%7D%20%7D%20%20%7D%7B%5Csqrt%5B3%5D%7B6%5E%7B2%7D%7D%20%20%7D%20%5C%5C%20%20%5C%5C%20%3D%20%20%5Chuge%20%5Cfrac%7B%282%20%2B%20%20%5Csqrt%5B3%5D%7B3%7D%20%29%5Csqrt%5B3%5D%7B6%7D%20%7D%7B%20%5Csqrt%5B3%5D%7B6%7D%20%5Ctimes%20%5Csqrt%5B3%5D%7B6%20%5E%7B2%7D%20%7D%7D%20%20%5C%5C%20%20%5C%5C%20%3D%20%20%5Chuge%20%5Cfrac%7B%282%20%5Csqrt%5B3%5D%7B6%7D%20%2B%20%20%5Csqrt%5B3%5D%7B3%7D%20%5Csqrt%5B3%5D%7B6%7D%20%29%7D%7B%20%20%5Csqrt%5B3%5D%7B6%20%5E%7B3%7D%20%7D%7D%20%20%5C%5C%20%20%5C%5C%20%3D%20%20%5Chuge%20%20%5Corange%7B%5Cfrac%7B2%20%5Csqrt%5B3%5D%7B6%7D%20%2B%20%20%5Csqrt%5B3%5D%7B18%7D%20%7D%7B%20%206%7D%20%20%7D)
Given :
a paddle boat travels upstream = 12 miles
a paddle boat travels downstream = 20 miles
speed of the current = 2 miles per hour
Let the speed of the boat =x
Let the time taken = t
We know the distance for upstream D= (boat speed - current speed) * time
the distance for downstream D= (boat speed + current speed) * time
Plug in all the values and variables in the distance
For upstream 12 = (x-2)t, then 
For downstream 20 = (x+2)t then 
we got two equations for t, equate it and solve for x

Cross multiply it
12(x+2) = 20(x-2)
12x + 24 = 20x - 40 (subtract 12x and add 40 on both sides)
64 = 8x
x= 8
the speed of the boat in still water = 8 miles per hour
Answer:
Yes Ben is correct
Step-by-step explanation:
For example:
If n² is the greater of the two consecutive square numbers, then the difference will be 2n-1. So for example, if you have two consecutive squares with the values of 25, and 36, their difference will be 11. Notice though that 11=2×6–1, so it conforms to 2n-1.
He has eaten 7/21 already. if he eats 9/21 from the 14/21 left, he will have 5/21 left. the answer is d
133=x + (x+5) + (x+14)
133 = 3x+19
3x=114
x= 114/3 =38
5+38 =43
38+14 =52
check: 38 +43 +52 = 133
3 sides are : 38, 43 & 52