Answer:
its 16
its 16 16 16 16 16 16 16 16 16 16 16 16 16
Okay! I think I figured it out.
So you know that A + B + C + D + E + F = 36 ft.
You also know that A + C = E and that B + D = F.
Now they give you the clue that E is 8 ft.
They also tell you that A, B, C, and D are consecutive numbers. Meaning that they are right next to each other so like 1, 2, 3, and 4.
Based on this, I got that A = 3 ft., B = 4 ft., C = 5 ft., and D = 6 ft. Then I made sure that 3 ft. + 5 ft. = 8ft. True. Then I concluded that F must be equal to 10 ft.
I added (A) 3 ft. + (B) 4 ft. + (C) 5 ft. + (D) 6 ft. + (E) 8 ft. + (F) 10 ft. = 36 ft.
Answer:
System A has 4 real solutions.
System B has 0 real solutions.
System C has 2 real solutions
Step-by-step explanation:
System A:
x^2 + y^2 = 17 eq(1)
y = -1/2x eq(2)
Putting value of y in eq(1)
x^2 +(-1/2x)^2 = 17
x^2 + 1/4x^2 = 17
5x^2/4 -17 =0
Using quadratic formula:
a = 5/4, b =0 and c = -17
Finding value of y:
y = -1/2x
System A has 4 real solutions.
System B
y = x^2 -7x + 10 eq(1)
y = -6x + 5 eq(2)
Putting value of y of eq(2) in eq(1)
-6x + 5 = x^2 -7x + 10
=> x^2 -7x +6x +10 -5 = 0
x^2 -x +5 = 0
Using quadratic formula:
a= 1, b =-1 and c =5
Finding value of y:
y = -6x + 5
y = -6(\frac{1\pm\sqrt{19}i}{2})+5
Since terms containing i are complex numbers, so System B has no real solutions.
System B has 0 real solutions.
System C
y = -2x^2 + 9 eq(1)
8x - y = -17 eq(2)
Putting value of y in eq(2)
8x - (-2x^2+9) = -17
8x +2x^2-9 +17 = 0
2x^2 + 8x + 8 = 0
2x^2 +4x + 4x + 8 = 0
2x (x+2) +4 (x+2) = 0
(x+2)(2x+4) =0
x+2 = 0 and 2x + 4 =0
x = -2 and 2x = -4
x =-2 and x = -2
So, x = -2
Now, finding value of y:
8x - y = -17
8(-2) - y = -17
-16 -y = -17
-y = -17 + 16
-y = -1
y = 1
So, x= -2 and y = 1
System C has 2 real solutions
Answer:
thats quadrant 2
Step-by-step explanation:
Simplified version: <span>9x^5 + 5x^3 + 7x^2 - 13</span>