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Ludmilka [50]
3 years ago
10

Follow me on brainy,and what is a+b+z+fg-y+up+f+r=​

Mathematics
1 answer:
pickupchik [31]3 years ago
7 0

Answer:

Sure why not.

Step-by-step explanation:

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What is blank/11 = 12/44 equivalent fractions
nordsb [41]

Answer:

3/11

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
A small rock falling from the top of a 124-ft-tall building with an initial downward velocity of -30ft/sec is modeled by the equ
Mandarinka [93]
You need to solve this for h(t)=0

<span>-16t^2-30t+124=0

This has two solutions, one is negative that does not make sense as time cannot be negative. 
The positive solution is t=2

So the interval where it is in the air is [0;2) 

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5 0
3 years ago
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Determine whether each expression is equivalent to 49^2t – 0.5.
vampirchik [111]

Answer:

None of the expression are equivalent to 49^{(2t - 0.5)}

Step-by-step explanation:

Given

49^{(2t - 0.5)}

Required

Find its equivalents

We start by expanding the given expression

49^{(2t - 0.5)}

Expand 49

(7^2)^{(2t - 0.5)}

7^2^{(2t - 0.5)}

Using laws of indices: (a^m)^n = a^{mn}

7^{(2*2t - 2*0.5)}

7^{(4t - 1)}

This implies that; each of the following options A,B and C must be equivalent to 49^{(2t - 0.5)} or alternatively, 7^{(4t - 1)}

A. \frac{7^{2t}}{49^{0.5}}

Using law of indices which states;

a^{mn} = (a^m)^n

Applying this law to the numerator; we have

\frac{(7^{2})^{t}}{49^{0.5}}

Expand expression in bracket

\frac{(7 * 7)^{t}}{49^{0.5}}

\frac{49^{t}}{49^{0.5}}

Also; Using law of indices which states;

\frac{a^{m}}{a^n} = a^{m-n}

\frac{49^{t}}{49^{0.5}} becomes

49^{t-0.5}}

This is not equivalent to 49^{(2t - 0.5)}

B. \frac{49^{2t}}{7^{0.5}}

Expand numerator

\frac{(7*7)^{2t}}{7^{0.5}}

\frac{(7^2)^{2t}}{7^{0.5}}

Using law of indices which states;

(a^m)^n = a^{mn}

Applying this law to the numerator; we have

\frac{7^{2*2t}}{7^{0.5}}

\frac{7^{4t}}{7^{0.5}}

Also; Using law of indices which states;

\frac{a^{m}}{a^n} = a^{m-n}

\frac{7^{4t}}{7^{0.5}} = 7^{4t - 0.5}

This is also not equivalent to 49^{(2t - 0.5)}

C. 7^{2t}\ *\ 49^{0.5}

7^{2t}\ *\ (7^2)^{0.5}

7^{2t}\ *\ 7^{2*0.5}

7^{2t}\ *\ 7^{1}

Using law of indices which states;

a^m*a^n = a^{m+n}

7^{2t+ 1}

This is also not equivalent to 49^{(2t - 0.5)}

6 0
3 years ago
Hey mm, i’m lost idk what to do •__•
IceJOKER [234]

To find the perimeter, we must add together the length of each side.

The tick mark on the lines means they are equal, so that means we have two lines that are equal to 10

26 + 10 + 35 + 5 + 10 + (38 - 10) = 114"

7 0
4 years ago
Mr. Flanders’ class sold doughnuts for $1.35 each and Mr.Rodriquez’s class sold cartons of milk for $1.08 each together the clas
saul85 [17]

Answer:

Part A: Let, the number of doughnuts = x and the number of carton milk = y.

Part B: We have, Mr. Flanders sold doughnut for $1.35 each and Mr. Rodriquez sold milk for $1.08 each.

As, they sold 85 items in total.

Thus, x + y = 85.

Moreover, they both earned $104.49 in total.

So, 1.35x + 1.08y = 104.49.

Hence, we get the system of equations,

1.35x + 1.08y = 104.49

x + y = 85.

Part C: Now, we will solve the system of equations,

As, x + y = 85 ⇒ y = 85 - x.

As, 1.35x + 1.08y = 104.49 ⇒ 1.35x + 1.08(85-x) = 104.49 ⇒ 1.35x + 91.8 - 1.08x = 104.49 ⇒ 0.27x = 12.69 ⇒ x = 47.

So, y = 85 - 47 ⇒ y = 38.

Thus, x = 47 and y = 38 is the solution.

Part D: Hence, we get that,

Number of doughnuts sold by Mr. Flanders is 47 and the number of carton milk sold by Mr. Rodriquez is 38.

4 0
3 years ago
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