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irakobra [83]
4 years ago
13

What is 0.3636... round to the nearest tenth?

Mathematics
1 answer:
miskamm [114]4 years ago
6 0
0.36. 
tenth position is b in . 0.ab
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What do you mean by that because I freak my don’t understand you alquestio
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3 years ago
Baker, Inc. uses the sum-of-the-years’-digits method to depreciate a $79,600.00 piece of equipment that has an estimated life of
Anton [14]
Using the sum of the years digits method

Step 1:

We sum up all the digits of the estimated life of equipment.

i.e. 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10 + 11 + 12 + 13 + 14 + 15 + 16 + 17 + 18 + 19 + 20 = 210

Step 2:

We count the years spent from the back. i.e. year 2 is equivalent to 19 in the years digits.

Given that the cost of the equipment is $79,600.00 with a salvage value of $4,000.00. This means that the depreciable amount of the equipment is given by $79,600.00 - $4,000.00 = $75,600.00

The depreciation charge on the equipment for year 1 is given by

\frac{20}{210} \times\$75,600=\$7,200

while the depreciation charge on the equipment for year 2 is given by

\frac{19}{210} \times\$75,600=\$6,840

The book value of an equipment is given by the cost of the equipment minus the accumulated depreciation.

Therefore, the book value of the equipment at the end of year 2 is given by

$79,600 - $7,200 - $6,840 = $65,560
6 0
4 years ago
If thewronskian w of f and g is 3e4t,and if f(t) = e2t,find g(t).
ehidna [41]
W(f(x),g(x))=\begin{vmatrix}f(x)&g(x)\\f'(x)&g'(x)\end{vmatrix}=f(x)g'(x)-g(x)f'(x)

We have f(t)=e^{2t}\implies f'(t)=2e^{2t}, so

W(f(t),g(t))=e^{2t}g'(t)-2e^{2t}g(t)=3e^{4t}
\implies e^{-2t}g'(t)-2e^{-2t}g(t)=3
\implies\dfrac{\mathrm d}{\mathrm dt}[e^{-2t}g(t)]=3
\implies e^{-2t}g(t)=\displaystyle\int3\,\mathrm dt
\implies e^{-2t}g(t)=3t+C
\implies g(t)=3te^{2t}+Ce^{2t}

where C is any arbitrary constant.
8 0
4 years ago
An animal park has lion,tigers and zebras.30% of the animals are lion and half the animals are zebras.If there are 120 animals a
arsen [322]
120×30/100=36
36 lions if there are 120 animals
8 0
3 years ago
Calculate the speed of a car that went a distance of 125 miles in 2 hours<br> time.
DerKrebs [107]

Answer:

62.5

Step-by-step explanation:

speed = distance / time taken

= 125/2

=62.5miles per hour

5 0
3 years ago
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