an atom of a certain element has 35 protons and has 7 valence electrons. which statement best identifies the element ?

Mathematics

1 answer:

Sonbull [250]3 years ago

3 0

Answer:

the number of protons identifies what element it is, since it has 35 protons it is Bromine

number of protons=atomic number

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808, 408, 208,108, 68 find out wrong number.

EastWind [94]

68 is the wrong number in the sequence 808, 408, 208,108, 68

<h3>What is Number system?</h3>

A number system is defined as a system of writing to express numbers.

Sequence is an enumerated collection of objects in which repetitions are allowed and order matters.

The given sequence is 808, 408, 208,108, 68

Eight hundred eight, Four hundred and eight, two hundred and eight, one hundred eight and sixty eight.

808, 408, 208,108, 68

Let us find the difference between the consecutive numbers

400, 200, 100, 40

As we observe the first three terms having the common ratio where as 40 and 100 has different ratio.

Hence, 68 is the wrong number in the sequence 808, 408, 208,108, 68

To learn more on Number system click:

brainly.com/question/22046046

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6 0

1 year ago

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Find the next 3 terms of the following sequence 22 21 18 13 6

love history [14]

-3,-14,-27. This sequence is subtracting the next odd number

8 0

3 years ago

Solve log8 12=x-2. Round your answer to four decimal places.

olganol [36]

Answer:

$\large\boxed{x\approx3.1950}$

Step-by-step explanation:

$\log_ab=c\iff a^c=b\\\\\log_812=x-2\iff8^{x-2}=12\\\\(2^3)^{x-2}=4\cdot3\qquad\text{use}\ (a^n)^m=a^{nm}\\\\2^{3(x-2)}=2^2\cdot3\qquad\text{use the distributive property}\\\\2^{3x-6}=2^2\cdot3\qquad\text{divide both sides by}\ 2^2\\\\\dfrac{2^{3x-6}}{2^2}=3\qquad\text{use}\ \dfrac{a^n}{a^m}=a^{n-m}\\\\2^{3x-6-2}=3\\\\2^{3x-8}=3\qquad\text{logarithm of both sides}\\\\\log_22^{3x-8}=\log_23\qquad\text{use}\ \log_aa^n=n\\\\3x-8=\log_23\qquad\text{add 8 to both sides}$