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3 years ago

Simplify. √20 v Assume that the variable represents a positive real number.

Mathematics

2 answers:

myrzilka [38]3 years ago

5 0

Answer:

2 sqrt(5)

Step-by-step explanation:

sqrt(20)

sqrt(4*5)

We know that sqrt(ab) = sqrt(a) sqrt(b)

sqrt(4) sqrt(5)

2 sqrt(5)

True [87]3 years ago

3 0

Answer:

$2\sqrt{5v}$

Step-by-step explanation:

We can treat 20v as a regular number and not a term.

To simplify this square root, we need to break it down into parts which can be squared.

$\sqrt{20v} = \sqrt{4\cdot5v}$

Square root of 4 is 2, so that goes outside the radical.

$2\sqrt{5v}$ .

Hope this helped!

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V125BC [204]

Using BEDMAS you follow the structure of what processes you need to do in the right mathematical order.

In this case, Brackets first, multiplication second, then adding.

Therefore answer he answer is C 184

8 0

2 years ago

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dalvyx [7]

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7 0

1 year ago

8n = -3m + 1; n = -2, 2, 4

bogdanovich [222]

I am assuming you want to solve for m in each case

8n = -3m + 1

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-16 = -3m + 1

-3m = -17

m = $\frac{17}{3}$

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16 = -3m + 1

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8 0

3 years ago

Read 2 more answers

Work out the product of

nignag [31]

That will be 4/4/7 hope this helps

5 0

2 years ago

64, –48, 36, –27, ...<br><br> Which formula can be used to describe the sequence?

nordsb [41]

Answer:

$\boxed{a_n \: = \: 64 \: \times \: ( - \frac{3}{4} ) ^{n \: - \: 1} }$

Step-by-step explanation:

We first compute the ratio of this geometric sequence.

$r \: = \: \frac{ - 48}{64} \\ \\ r \: = \: \frac{36}{ - 48} \\ \\ r \: = \: \frac{ - 27}{36}$

We simplify the fractions:

$r \: = \: - \frac{3 }{4} \\ \\ r \: = \: - \frac{3 }{4} \\ \\ r \: = \: - \frac{3 }{4}$

We deduce that it is the common ratio because it is the same between each pair.

$r \: = \: - \frac{3 }{4}$

We use the first term and the common ratio to describe the equation:

$a_1 \: = \: 64; \: r \: = \: - \frac{3 }{4}$

<h3>We apply the data in this formula:</h3>

$\boxed{a_n \: = \: a_1 \: \times \: {r}^{ n \: - \: 1} }$

_______________________

<h3>We apply:</h3>

$\boxed {\bold{a_n \: = \: 64 \: \times \: {( - \frac{3}{4} )}^{ n \: - \: 1} }}$

<u>Data</u>: The unknown "n" is the term you want

<h3><em><u>MissSpanish</u></em></h3>

4 0

2 years ago