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3 years ago

Simplify. √20 v Assume that the variable represents a positive real number.

Mathematics

2 answers:

myrzilka [38]3 years ago

5 0

Answer:

2 sqrt(5)

Step-by-step explanation:

sqrt(20)

sqrt(4*5)

We know that sqrt(ab) = sqrt(a) sqrt(b)

sqrt(4) sqrt(5)

2 sqrt(5)

True [87]3 years ago

3 0

Answer:

$2\sqrt{5v}$

Step-by-step explanation:

We can treat 20v as a regular number and not a term.

To simplify this square root, we need to break it down into parts which can be squared.

$\sqrt{20v} = \sqrt{4\cdot5v}$

Square root of 4 is 2, so that goes outside the radical.

$2\sqrt{5v}$ .

Hope this helped!

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A certain forest covers an area of

iVinArrow [24]

Answer:

2598 square kilometers

Step-by-step explanation:

Hello

Step 1

year one

using a rule of three is possible to find how much is 8.75 od 4500 km2

Let

4500 km2 ⇒ 100$

x?km2 ⇒8.75

do the relation and isolate x

$4500:100\\x:8.75\\\frac{4500}{100}=\frac{x}{8.75}\\x=\frac{4500*8.75}{100} \\x=393.75\\$

at the end of the year one, the area will be

4500-393.75=4106.25

this will be the initial area for the year 2.

Step 2

repite the step 1 with area initial =4106.25 km2

4106.25 km2 ⇒ 100$

x?km2 ⇒8.75

do the relation and isolate x

$4106.25:100\\x:8.75\\\frac{4106.25}{100}=\frac{x}{8.75}\\x=\frac{4106.25*8.75}{100} \\x=359.29\\$

at the end of the year 2, the area will be

4106-359.29=3746.70

this will be the initial area for the year 3.

Step 3

repite the step 1 with area initial =4106.25 km2

3746.70 km2 ⇒ 100$

x?km2 ⇒8.75

do the relation and isolate x

$3746.70:100\\x:8.75\\\frac{3746.70}{100}=\frac{x}{8.75}\\x=\frac{3746.7*8.75}{100} \\x=327.83\\$

at the end of the year 3, the area will be

3746.70-327.83=3419.09

this will be the initial area for the year 4.

Step 4

year four

repite the step 1 with area initial =3419.09 km2

3419.09 km2 ⇒ 100$

x?km2 ⇒8.75

do the relation and isolate x

$3419.09:100\\x:8.75\\\frac{3419.09}{100}=\frac{x}{8.75}\\x=\frac{3419.09*8.75}{100} \\x=299.17\\$

at the end of the year 4, the area will be

3419.09-299.173=3119.82

this will be the initial area for the year 5.

Step 5

year five

repite the step 1 with area initial =3119.82 km2

3119.82 km2 ⇒ 100$

x?km2 ⇒8.75

do the relation and isolate x

$3119.82:100\\x:8.75\\\frac{3119.82}{100}=\frac{x}{8.75}\\x=\frac{3119.82*8.75}{100} \\x=272.99\\$

at the end of the year 5, the area will be

3119.82-272.99=2846.92

this will be the initial area for the year 6.

Step 6

year six

repite the step 1 with area initial =2846.92km2

2846.92 km2 ⇒ 100$

x?km2 ⇒8.75

do the relation and isolate x

$2846.92:100\\x:8.75\\\frac{2846.92}{100}=\frac{x}{8.75}\\x=\frac{2846.92*8.75}{100} \\x=249.10\\$

at the end of the year six, the area will be

2846.92-249.10=2597.82 square kilometers

Have a great day.

8 0

3 years ago

1.what is the vertex of the graph? (see attachment)

AfilCa [17]

Hello :
here is a solution :

5 0

3 years ago

Read 2 more answers

a rectangular garden measures 22.7 m by 16.6 m how many meters of fencing materials are needed to enclose it the fencing materia

pantera1 [17]

Answer:

78.6m of fencing

That would cost $982.50

Step-by-step explanation:

Perimeter: 2(22.7)+2(16.6)=P

P = 78.6

Cost: 78.6*12.50

C = 982.50

8 0

3 years ago

Limit as x approaches pi/2 of cos(x)/x-(pi/2)

nalin [4]

plug in x=0 gives 0/0. This is one of the indeterminate forms (some others are ∞/∞ and 0·∞) use L'Hospital's Rule.
Differentiate the top and bottom of the fraction:
lim (cos x) / (x - π/2) => lim (-sin x) / (1 - 0)
Now you can substitute x = π/2 without problem
lim = -1/1= -1

4 0

3 years ago

A Positive b Undefined c Negative d Zero

VLD [36.1K]

I believe that the answer would be
A. Positive

4 0

3 years ago

Read 2 more answers