Your answer is 9 and idk how
Calculator does it all.
Answer:
$500
Step-by-step explanation:
We can find the original price of the camera through a proportion. A proportion is an equation where two ratios or fractions are equal. The ratios or fractions compare like quantities.
<u>Second Discoun</u>t
20% off means we paid 80%. We know we paid $328 of some price.
![\frac{80}{100} =\frac{328}{y} \\](https://tex.z-dn.net/?f=%5Cfrac%7B80%7D%7B100%7D%20%3D%5Cfrac%7B328%7D%7By%7D%20%5C%5C)
I can now cross-multiply by multiplying numerator and denominator from each ratio.
![80y=100(328)\\80y=32800](https://tex.z-dn.net/?f=80y%3D100%28328%29%5C%5C80y%3D32800)
I now solve for y by dividing by 80.
![\frac{80y}{80} =\frac{32800}{80}](https://tex.z-dn.net/?f=%5Cfrac%7B80y%7D%7B80%7D%20%3D%5Cfrac%7B32800%7D%7B80%7D)
y=410
The price after the first discount was $410.
<u>First Discount</u>
We will repeat the steps above with $410. 18% off means we paid 82%.
![\frac{82}{100}=\frac{410}{y}](https://tex.z-dn.net/?f=%5Cfrac%7B82%7D%7B100%7D%3D%5Cfrac%7B410%7D%7By%7D)
I can now cross-multiply by multiplying numerator and denominator from each ratio.
![82y=100(410)\\82y=41000](https://tex.z-dn.net/?f=82y%3D100%28410%29%5C%5C82y%3D41000)
I now solve for y by dividing by 82.
![\frac{82y}{82} =\frac{41000}{82}](https://tex.z-dn.net/?f=%5Cfrac%7B82y%7D%7B82%7D%20%3D%5Cfrac%7B41000%7D%7B82%7D)
y=500
The original price was $500.
Answer:
We need to demontrate
![m \angle MJL = \frac{1}{2}arc(KL)](https://tex.z-dn.net/?f=m%20%5Cangle%20MJL%20%3D%20%5Cfrac%7B1%7D%7B2%7Darc%28KL%29)
As you can see in the figure below, angle MJL is an inscribed angle for Circle M, that means we can use the inscribed angle theorem to demonstrate the proposition above.
<h3>Therorem.</h3>
<em>The angle formed by two intersecting chords with vertex on the circumference is equal to one-half of the intercepted arc.</em>
<em />
Notice that the theorem says a chord. However, a diameter is a chord by definition, because a chord is a segment that unites to points of the circumference, and a diameter does that too.
Therefore, based on the inscribed angle arc theorem, we have
![m \angle MJL = \frac{1}{2}arc(KL)](https://tex.z-dn.net/?f=m%20%5Cangle%20MJL%20%3D%20%5Cfrac%7B1%7D%7B2%7Darc%28KL%29)
What is this??? This is confusing