Answer:
Let the function be Node* ins(Node *root,int k)
if root node is NULL then return new node with data equal to k.
If the k <root->data
root->left=ins(root->left,k);
else if k >root->data
root->right =ins(root->right,k);
At last return root.
Explanation:
Node is always inserted at the at the leaf node.We will search k in the tree if we hit a the leaf node the new node is inserted as the child of the leaf node.
Answer:
The rules which could trigger at any period in time are referred to as the conflict set. A programming bug/conflict can occur when two programs compete for the same resource such as memory or register etc.
A Conflict Resolution Strategy is is a protocol which highlights which decision will be triggered first.
The best way to resolve conflict is to first determine the kind of conflict it is. Hardware conflicts can be resolved by first troubleshooting the hardware and in some instances unplugging the hardware causing the conflict.
When hardware creates conflicts it may be due to a driver issue. reverting to an old driver or updating the existing one may solve the problem.
Software conflicts can be resolved by installing updates or complete uninstallation.
Cheers!

int y = (int) y;
int x = y;
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Answer:
Three ways to increase the value of variable are given below. To eleborate the answer, I am taking a variable x that need to be increase.
- x=x+1
- x++
- x+=1
Explanation:
There are three ways to increase the value of variable.
1. x= x+1
In this case, each time value of x (variable) is incremented and stored in that variable. This equation increase the value of x by 1 each time. For Example
if x=1
then in first iteration
x= x+1 = 2;
If we want to increase the value of x by more than 1, we can add that value with x, as x+2, x+3 and so on.
2. x++
This will increment the value of x by 1. If we use this equation multiple time in program, each time it will increase 1 in value of x.
3. x+=1
This also works same as equation 1. It will increment 1 in this form and can be changed with 2, 3 and so on.