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3 years ago

Lidge points from all the parts i

Business

1 answer:

Over [174]3 years ago

3 0

Answer:

a frequency distribution is an overview of all different values in some variable and the number of times they occur that is frequency distribution tells how frequencies are distributed over values frequency distributions are mostly used for summarizing categorical variables.

in non probability sampling the sample is selected based on the random criteria and not every member of the population has a chance of being included, non probability sampling methods include convenience sampling voluntary response sampling purposive sampling snowball sampling and quota sampling.

in statistics a central tendency (or measure of central tendency) is a central or typical value for a probability distribution. ... Colloquially measures of central tendency are often called averages the term central tendency dates from the late 1920s

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Krall Company recently had a computer malfunction and lost a portion of its accounting records. The company has reconstructed so

victus00 [196]

Answer and Explanation:

The missing amount is as follows:

<u>Return on Profit Investment Operation Sales Average </u>

<u>Investment Margin Turnover Income Revenue Invested Assets</u>

5% 10% 0.50 $70,000 $700,000 $1,400,000

(0.50% of 10) ($70,000 ($700,000 ÷

÷ $700,000) $1,400,000)

4% 8% 0.50 $100,000 $1,250,000 $2,500,000

(0.50 of 8%) (0.50 of $2,500,000)

15% 12% 1.25 $168,000 $1,400,000 $1,120,000

(1.25 of 12%) (12% of $1,400,000) ($1,400,000 ÷ 1.25)

10% 5% 2 $30,000 $600,000 $300,000

($30,000 ÷ $600,000) (10% of $300,000) ($600,000 ÷ 2)

4 0

3 years ago

A well insulated 3-m X 4-m X 6-m room initially at 7 degrees C is heated by the radiator of a steam heating system. The radiator

poizon [28]

Answer:

The average temperature of air in 45 minutes is 10.74°C

Explanation:

Given

Time t = 45 minutes

Initial Air Temperature, T1 = 7°C

Fan work W = 120W

Radiator Volume = V1 = 15L

Initial Steam Pressure = P1 = 200kPa

Initial Steam Temperature = Ts1 = 200°C

Final Steam Pressure = P2 = 100kPa

The radiator is our system.

We take the system as a close system.

The energy balance is given as follows

-Qout = ∆U

-Qout = m(u2 - u1)

Calculating u2

From steam table (see attachment below)

At P1 and Ts1

P1 = 200kPa, Ts1 = 200°C

u1 = 2654.6KJ/Kg

v1 = 1.08049 m³/Kg

At P2 = 100kPa, v1 = v2

vf = 0.001043m³, vg = 1.6941m³/kg uf = 417.4kj/kg ufg = 2088.2kj/kg

x2 = (v2 - vf)/(vg - vf)

x2 = (1.08049 - 0.001043)/(1.6941 - 0.001043)

x2 = 1.079447/1.693057

x2 = 0.63757

u2 = uf + x2ufg

u2 = 417.4 + 0.63757 * 2088.2

u2 = 417.4 + 1331.374

u2 = 1748.774

Solving for m

m = V1/v1

m = 15L/1.08049

m = 0.015/1.08049

m = 0.01388Kg

So, -Qout = m(u2 - u1) becomes

0.01388(1748.774 - 2654.6)

= 0.01388 * -905.826

= -12.572

-Qout = -12.572

So, Qout = 12.572KJ

The dimensions of the room is 3 * 4 * 5.

The mass and volume of air in the room is given by

Volume = 3 * 4 * 6 = 72m³

Mass = P * V/RT

Where R = Gas Constant = 0.287

T = T1 = 7°C = 273+ 7 = 280K

P = P2 = 100kPa

Mass = (100 * 72)/(0.287 * 280)

Mass = 7200/80.36

Mass = 89.597Kg

The amount of work is defined by

Work = Fan work W * Time t

Work = 120 * 45 minutes

Work = 120 * 45 * 60seconds

Work = 324000J

Work (fan, in) = 324KJ

Taking the air in the room as the system

The energy balance is as follows

∆Energy = E(in) - E(out)

E(in) = Q(out) + W(fan,in)

E(out) = W(out)

∆Energy = ∆U

So, we have

∆U = Q(out) + W(fan,in) - W(out)

∆U + W(out) = Q(out) + W(fan,in)

∆U + W(out) = 12.572 + 324

∆U + W(out) = 336.572

∆U + W(out) = ∆H (Change in heat energy)

This is given by mc(T2 - T1)

Where m = 89.597kg

c = specific heat of air at constant pressure = 1.005

T1 = 7°C

Substituting in these values, we have

336.572 = 89.597 *1.005 (T2 - 7)

=> 336.572 = 90.044985(T2 - 7)

T2 - 7 = 3.74

T2 = 3.74 + 7

T2 = 10.74°C

8 0

4 years ago

According to the Uniform Commercial Code's interpretation of an open quantity term, if the quantity term is left open in a contr

Pie

According to the Uniform Commercial Code's interpretation of an open quantity term, if the quantity term is left open in a contract for the sale of goods courts generally have no basis for determining a remedy.

<h3>What do you mean by Uniform Commercial Code?</h3>

The uniform Commercial code states that a sale consists of the passing of title from the seller to the buyer for a price.

According to the Uniform Commercial code's interpretation of an open quantity term, if the quantity term is left open in a contract for the sale of goods, courts have no basis for the determination of remedy.

Learn more about uniform commercial code here:

brainly.com/question/8476938

#SPJ1

3 0

3 years ago

Suppose Columbia Sportswear Company had accounts receivable of $206,090,000 at the beginning of a recent year, and $267,085,000

scZoUnD [109]

Answer:

The amount of cash receipts from customers: $1,032,865,000

Explanation:

Assuming that all Sales revenue was on credit sales.

In Suppose Columbia Sportswear, Sales revenue was $1,093,860,000, accounts receivable in the year increased $1,093,860,000. Basing on formula:

Accounts receivable at year-end = Accounts receivable at the beginning of the year + Accounts receivable increasing in the year - Accounts receivable decreasing in the year

Thefore:

Accounts receivable decreasing in the year = Accounts receivable at the beginning of the year + Accounts receivable increasing in the year - Accounts receivable at year-end = $206,090,000 + $1,093,860,000 - $267,085,000 = $1,032,865,000

This is also the amount of cash receipts from customers.

3 0

3 years ago

The facility is implementing a new information system that will require conversion of healthcare data. the conversion is:

Gnoma [55]

Required when data is stored differently or changes are being made to data collection

3 0

3 years ago